import { CAMPAIGN, LEVELS } from './levels.js';
import { ARCHIVED_LEVELS } from './levels-archive.js';
import { EXPERIENCE_CAMPAIGN, EXPERIENCE_LEVELS } from './levels-v04.js';
import { PRODUCTION_CAMPAIGN, PRODUCTION_LEVELS } from './levels-v05.js';
import { TUTORIAL_LEVELS } from './tutorial-levels.js';
import { C50_CAMPAIGN, C50_LEVELS } from './levels-c50.js';

// Public layout versions are distinct from the level JSON schema's `version: 1`.
// Historical layouts stay intact; all editions share the current game rules.
export const CAMPAIGN_VERSIONS = [
  {
    id:'v0.1', name:'最初设计', description:'最初的 24 关，保留原始布局与顺序。',
    chapters:['转盘初体验','糖果回旋','碰撞大挑战'], chapterSize:8,
    levels:ARCHIVED_LEVELS['v0.1'], legacyStorageKeys:['hex-trails-v2'],
  },
  {
    id:'v0.2', name:'直线较多版', description:'扩展为 48 关，直线路径较多，按舒展与挑战交替推进。',
    chapters:['看见出口','转出新路','连成节奏','轻巧解结','展开天地','从容变换','长路常新','自在回响'], chapterSize:6,
    levels:ARCHIVED_LEVELS['v0.2'], legacyStorageKeys:['hex-trails-observe-v3-r1','hex-trails-observe-v3'],
  },
  {
    id:'v0.3', name:'弯轨观察版', description:'48 关弯轨观察版本，以单弯与连续消除为主。',
    chapters:CAMPAIGN.chapters, chapterSize:CAMPAIGN.chapterSize,
    levels:LEVELS, legacyStorageKeys:[`hex-trails-${CAMPAIGN.id}-r${CAMPAIGN.revision||1}`],
  },
  {
    id:'v0.4', name:'长路与惊喜', description:'20 关全新体验：看棋子沿长路巡游，转一下放出朝内棋子，再逐层解开整盘。',
    chapters:EXPERIENCE_CAMPAIGN.chapters, chapterSize:EXPERIENCE_CAMPAIGN.chapterSize,
    levels:EXPERIENCE_LEVELS, legacyStorageKeys:[],
  },
  {
    id:'v0.5', name:'千段轨迹', description:'1000 关新旅程：沿长路巡游、清挡放行，转出花瓣与交织的出口。难度为结构预估，持续通过试玩打磨。',
    chapters:PRODUCTION_CAMPAIGN.chapters, chapterSize:PRODUCTION_CAMPAIGN.chapterSize,
    levels:PRODUCTION_LEVELS, tutorials:TUTORIAL_LEVELS, legacyStorageKeys:[],
  },
  {
    id:C50_CAMPAIGN.id, name:C50_CAMPAIGN.name, description:C50_CAMPAIGN.description,
    chapters:C50_CAMPAIGN.chapters, chapterSize:C50_CAMPAIGN.chapterSize, levels:C50_LEVELS,
    legacyStorageKeys:[],
  },
];
export const DEFAULT_CAMPAIGN_VERSION = 'v0.5';
export function campaignVersion(id) {
  return CAMPAIGN_VERSIONS.find(c=>c.id===id)||CAMPAIGN_VERSIONS.find(c=>c.id===DEFAULT_CAMPAIGN_VERSION);
}