01 · 入门 · 认识差值与中间格数量
展开作者解与路线
c2 → c1 → c0 → c3 → c4 → c5
推理依据
- c1→c4：3 次移动，作者步号 2→5
关键分叉：第 2 步应走 c1，诱惑路线走 c5。排除依据：相对步差不符。
逐项机制必要性反例
解除 relation:0 后：c2 → c5 → c4 → c1 → c0 → c3
每格一次。A → B +d：B 的步号减去 A 的步号等于 d；+4 是四次移动，中间有三格。
原始盘面和作者解分开展示。标题是设计任务，真人推理路径与难度仍需试玩验证。数字、窗口、方向、类别和开关显示在格内；步差与先后关系见逐关推理依据。
c2 → c1 → c0 → c3 → c4 → c5
关键分叉：第 2 步应走 c1，诱惑路线走 c5。排除依据：相对步差不符。
解除 relation:0 后：c2 → c5 → c4 → c1 → c0 → c3
c1 → c0 → c3 → c6 → c7 → c4 → c5 → c2
关键分叉：第 2 步应走 c0，诱惑路线走 c2。排除依据：相对步差不符。
解除 relation:0 后：c1 → c2 → c5 → c4 → c7 → c6 → c3 → c0
c0 → c4 → c5 → c1 → c2 → c3 → c7 → c6 → c9 → c8
关键分叉：第 4 步应走 c1，诱惑路线走 c8。排除依据：相对步差不符。
解除 relation:0 后：c0 → c4 → c5 → c8 → c9 → c6 → c7 → c3 → c2 → c1
c3 → c2 → c1 → c0 → c4 → c8 → c9 → c10 → c11 → c7 → c6 → c5
关键分叉：第 2 步应走 c2，诱惑路线走 c7。排除依据：相对步差不符。
解除 relation:0 后：c3 → c7 → c11 → c10 → c9 → c5 → c6 → c2 → c1 → c0 → c4 → c8
解除 relation:1 后：c3 → c2 → c1 → c0 → c4 → c8 → c9 → c5 → c6 → c7 → c11 → c10
c8 → c4 → c0 → c1 → c2 → c3 → c7 → c11 → c10 → c6 → c5 → c9 → c12 → c13
关键分叉：第 5 步应走 c2，诱惑路线走 c5。排除依据：相对步差不符。
解除 relation:0 后：c8 → c4 → c0 → c1 → c5 → c6 → c2 → c3 → c7 → c11 → c10 → c9 → c12 → c13
解除 relation:1 后：c8 → c4 → c0 → c1 → c2 → c3 → c7 → c11 → c10 → c13 → c12 → c9 → c5 → c6
c8 → c12 → c13 → c9 → c10 → c14 → c15 → c11 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c6
关键分叉：第 4 步应走 c9，诱惑路线走 c14。排除依据：相对步差不符。
解除 relation:0 后：c8 → c12 → c13 → c14 → c15 → c11 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c6 → c10 → c9
解除 relation:1 后：c8 → c12 → c13 → c9 → c5 → c4 → c0 → c1 → c2 → c3 → c7 → c6 → c10 → c11 → c15 → c14
c15 → c11 → c7 → c3 → c2 → c6 → c10 → c9 → c5 → c1 → c0 → c4 → c8 → c12 → c13 → c16 → c17 → c14
关键分叉：第 7 步应走 c10，诱惑路线走 c5。排除依据：相对步差不符。
解除 relation:0 后：c15 → c11 → c7 → c3 → c2 → c6 → c5 → c1 → c0 → c4 → c8 → c12 → c13 → c9 → c10 → c14 → c17 → c16
解除 relation:1 后：c15 → c11 → c10 → c9 → c5 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c12 → c13 → c16 → c17 → c14
解除 relation:2 后：c15 → c11 → c7 → c3 → c2 → c6 → c10 → c9 → c5 → c1 → c0 → c4 → c8 → c12 → c13 → c14 → c17 → c16
c15 → c11 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c12 → c13 → c9 → c5 → c6 → c10 → c14 → c18 → c17 → c16
关键分叉：第 1 步应走 c15，诱惑路线走 c8。排除依据：相对步差不符。
解除 relation:0 后：c8 → c4 → c0 → c1 → c5 → c9 → c13 → c12 → c16 → c17 → c18 → c14 → c15 → c11 → c10 → c6 → c2 → c3 → c7
解除 relation:1 后：c15 → c14 → c18 → c17 → c16 → c12 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c11 → c10 → c6 → c5 → c9 → c13