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<!doctype html><html lang="zh-CN"><meta charset="utf-8"><meta name="viewport" content="width=device-width,initial-scale=1"><title>200关DEMO · 设计评审</title><style>body{max-width:920px;margin:24px auto;padding:0 18px;background:#f7f5fb;color:#303047;font:15px/1.7 system-ui,'Microsoft YaHei'}article{background:white;border:1px solid #ddd5ed;border-radius:16px;padding:20px;margin:20px 0;break-inside:avoid}.boards{display:flex;gap:24px;flex-wrap:wrap}figure{margin:0;width:380px;max-width:100%}svg{max-height:450px;width:100%}details{cursor:pointer}a{color:#6552aa}@media print{body{background:white}article{border:none;page-break-after:always}} </style><a href="index.html">进入试玩</a><h1>200关DEMO · 200关设计评审</h1><p>每格一次;数字为访问步号,各关显示当前启用规则。</p><p>原始盘面和作者解分开展示。标题是设计任务,真人推理路径与难度仍需试玩验证。数字、窗口、方向、类别和开关显示在格内;步差与先后关系见逐关推理依据。</p><article><h2>1 · 走遍每格 · 引导 · 第一笔</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 153.33333333333331" role="img" aria-label="引导 · 第一笔"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><text x="76.66666666666666" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="76.66666666666666" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t0</text><text x="190" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="190" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t1</text><text x="303.3333333333333" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="303.3333333333333" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t2</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 153.33333333333331" role="img" aria-label="引导 · 第一笔"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polyline points="76.66666666666666,76.66666666666666 190,76.66666666666666 303.3333333333333,76.66666666666666" fill="none" stroke="#7963c9" stroke-width="5" opacity=".4"/><text x="76.66666666666666" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="76.66666666666666" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t0</text><text x="190" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">2</text><text x="190" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t1</text><text x="303.3333333333333" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="303.3333333333333" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t2</text></svg></figure><p>t0 → t1 → t2</p></details></div><h3>推理依据</h3><ul></ul><p>关键分叉:第 0 步应走 t0,诱惑路线走 数字不符的候选路线。排除依据:基础数字约束。</p><details><summary>逐项机制必要性反例</summary></details></article><article><h2>2 · 走遍每格 · 先收短支路</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="先收短支路"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 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fill="#665c78">c3</text><text x="190" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="190" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="303.3333333333333" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="76.66666666666666" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">6</text><text x="76.66666666666666" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="190" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="190" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="先收短支路"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 133.33333333333331,133.33333333333331 133.33333333333331,246.66666666666666 20,246.66666666666666" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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font-weight="700">7</text><text x="76.66666666666666" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="190" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">4</text><text x="190" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="303.3333333333333" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="76.66666666666666" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">6</text><text x="76.66666666666666" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="190" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">5</text><text x="190" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text></svg></figure><p>c1 → c2 → c5 → c4 → c7 → c6 → c3 → c0</p></details></div><h3>推理依据</h3><ul></ul><p>关键分叉:第 0 步应走 c1,诱惑路线走 数字不符的候选路线。排除依据:基础数字约束。</p><details><summary>逐项机制必要性反例</summary></details></article><article><h2>3 · 走遍每格 · 引导 · 整块一步</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 125" role="img" aria-label="引导 · 整块一步"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 275,20 275,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><text x="62.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="62.5" 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数字不符的候选路线。排除依据:基础数字约束。</p><details><summary>逐项机制必要性反例</summary></details></article><article><h2>4 · 走遍每格 · 大块一步</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="大块一步"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 327.5,122.5 225,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 122.5,122.5 122.5,225 20,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,122.5 327.5,122.5 327.5,327.5 122.5,327.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,225 122.5,225 122.5,327.5 20,327.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,327.5 122.5,327.5 122.5,430 20,430" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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y="165.75" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="71.25" y="183.75" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="225" y="217" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">5</text><text x="225" y="235" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="71.25" y="268.25" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="71.25" y="286.25" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="71.25" y="370.75" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">7</text><text x="71.25" y="388.75" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="173.75" y="370.75" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">6</text><text x="173.75" y="388.75" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text></svg></figure><p>c3 → c0 → c1 → c2 → c4 → c7 → c6 → c5</p></details></div><h3>推理依据</h3><ul></ul><p>关键分叉:第 0 步应走 c3,诱惑路线走 数字不符的候选路线。排除依据:基础数字约束。</p><details><summary>逐项机制必要性反例</summary></details></article><article><h2>5 · 走遍每格 · 引导 · 认识异形</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 210" role="img" aria-label="引导 · 认识异形"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 275,20 275,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><text x="62.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="62.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t0</text><text x="175.83333333333331" y="82.83333333333334" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="175.83333333333331" y="100.83333333333334" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t1</text><text x="317.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="317.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t2</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 210" role="img" aria-label="引导 · 认识异形"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 275,20 275,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polyline points="62.5,62.5 175.83333333333331,90.83333333333334 317.5,62.5" fill="none" stroke="#7963c9" stroke-width="5" opacity=".4"/><text x="62.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="62.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t0</text><text x="175.83333333333331" y="82.83333333333334" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">2</text><text x="175.83333333333331" y="100.83333333333334" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t1</text><text x="317.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="317.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t2</text></svg></figure><p>t0 → t1 → t2</p></details></div><h3>推理依据</h3><ul></ul><p>关键分叉:第 0 步应走 t0,诱惑路线走 数字不符的候选路线。排除依据:基础数字约束。</p><details><summary>逐项机制必要性反例</summary></details></article><article><h2>6 · 走遍每格 · 大块的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="大块的选择"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 246.66666666666666,133.33333333333331 246.66666666666666,246.66666666666666 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font-family="system-ui" font-size="10" fill="#665c78">c1</text><text x="303.3333333333333" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="303.3333333333333" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="114.44444444444444" y="219.77777777777777" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="114.44444444444444" y="237.77777777777777" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="303.3333333333333" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="190" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="190" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="大块的选择"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 246.66666666666666,133.33333333333331 246.66666666666666,246.66666666666666 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font-weight="700">6</text><text x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="190" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="190" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text></svg></figure><p>c5 → c3 → c0 → c1 → c2 → c4</p></details></div><h3>推理依据</h3><ul></ul><p>关键分叉:第 0 步应走 c5,诱惑路线走 数字不符的候选路线。排除依据:基础数字约束。</p><details><summary>逐项机制必要性反例</summary></details></article><article><h2>7 · 走遍每格 · 引导 · 永久墙</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="引导 · 永久墙"><polygon points="20,20 190,20 190,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 360,20 360,190 190,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 190,190 190,360 20,360" 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font-size="10" fill="#665c78">c8</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="绕过去就好"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 133.33333333333331,133.33333333333331 133.33333333333331,246.66666666666666 20,246.66666666666666" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,133.33333333333331 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x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="76.66666666666666" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="76.66666666666666" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="190" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">2</text><text x="190" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text><text x="303.3333333333333" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="303.3333333333333" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text></svg></figure><p>c8 → c7 → c6 → c3 → c0 → c1 → c2 → c5 → c4</p></details></div><h3>推理依据</h3><ul><li>墙 c1—c4 封闭该邻接</li></ul><p>关键分叉:第 7 步应走 c2,诱惑路线走 c4。排除依据:永久墙不能穿过。</p><details><summary>逐项机制必要性反例</summary><p>解除 wall:0 后:c8 → c7 → c6 → c3 → c0 → c1 → c4 → c5 → c2</p></details></article><article><h2>9 · 走遍每格 · 墙的小径</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 266.66666666666663" role="img" aria-label="墙的小径"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 133.33333333333331,133.33333333333331 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font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="190" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c1</text><text x="303.3333333333333" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="303.3333333333333" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="76.66666666666666" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="76.66666666666666" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="190" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="190" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 266.66666666666663" role="img" aria-label="墙的小径"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 133.33333333333331,133.33333333333331 133.33333333333331,246.66666666666666 20,246.66666666666666" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,133.33333333333331 246.66666666666666,133.33333333333331 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→ c0 → c3 → c4</p></details></div><h3>推理依据</h3><ul><li>墙 c1—c4 封闭该邻接</li></ul><p>关键分叉:第 3 步应走 c0,诱惑路线走 c4。排除依据:永久墙不能穿过。</p><details><summary>逐项机制必要性反例</summary><p>解除 wall:0 后:c2 → c1 → c4 → c3 → c0</p></details></article><article><h2>10 · 走遍每格 · 第一笔</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 266.66666666666663" role="img" aria-label="第一笔"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 133.33333333333331,133.33333333333331 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font-weight="700"></text><text x="303.3333333333333" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="76.66666666666666" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="76.66666666666666" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="190" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="190" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 266.66666666666663" role="img" aria-label="第一笔"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" 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font-weight="700"></text><text x="190" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t4</text><text x="303.3333333333333" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t5</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 266.66666666666663" role="img" aria-label="引导 · 左右直行"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 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fill="#665c78">t5</text></svg></figure><p>t0 → t1 → t2 → t5 → t4 → t3</p></details></div><h3>推理依据</h3><ul><li>t1 必须上下直行</li></ul><p>关键分叉:第 2 步应走 t1,诱惑路线走 t3。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:t1 后:t0 → t3 → t4 → t1 → t2 → t5</p></details></article><article><h2>14 · 认识通道 · 枢纽留后</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="枢纽留后"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" 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text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="62.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="62.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text><text x="147.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="147.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="枢纽留后"><polygon 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c3 → c4</p></details></div><h3>推理依据</h3><ul><li>c7 必须左右直行</li></ul><p>关键分叉:第 7 步应走 c6,诱惑路线走 c4。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c7 后:c0 → c1 → c2 → c5 → c8 → c7 → c4 → c3 → c6</p></details></article><article><h2>17 · 认识通道 · 上下通道</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="上下通道"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 327.5,122.5 225,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 122.5,122.5 122.5,225 20,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,122.5 225,122.5 225,225 122.5,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,122.5 327.5,122.5 327.5,225 225,225" fill="#f1eef9" 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font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">9</text><text x="232.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10</text></svg></figure><p>c10 → c6 → c3 → c0 → c1 → c2 → c5 → c9 → c8 → c7 → c4</p></details></div><h3>推理依据</h3><ul></ul><p>关键分叉:第 0 步应走 c10,诱惑路线走 数字不符的候选路线。排除依据:基础数字约束。</p><details><summary>逐项机制必要性反例</summary></details></article><article><h2>21 · 颜色接力 · 引导 · 蓝橙交替</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="引导 · 蓝橙交替"><polygon points="20,190 190,190 190,360 20,360" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,20 360,20 360,190 20,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,190 360,190 360,360 190,360" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><text x="105" y="267" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="105" y="285" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t0 · ○</text><text x="190" y="97" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="190" y="115" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t1</text><text x="275" y="267" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="275" y="285" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t2</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="引导 · 蓝橙交替"><polygon points="20,190 190,190 190,360 20,360" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,20 360,20 360,190 20,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,190 360,190 360,360 190,360" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polyline points="105,275 190,105 275,275" fill="none" stroke="#7963c9" stroke-width="5" opacity=".4"/><text x="105" y="267" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="105" y="285" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t0 · ○</text><text x="190" y="97" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">2</text><text x="190" y="115" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t1 · △</text><text x="275" y="267" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="275" y="285" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t2 · ○</text></svg></figure><p>t0 → t1 → t2</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li></ul><p>关键分叉:第 2 步应走 t1,诱惑路线走 t2。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:t0 → t2 → t1</p></details></article><article><h2>22 · 颜色接力 · 蓝橙第一步</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="蓝橙第一步"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 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fill="#665c78">c11</text></svg></figure><p>c8 → c2 → c7 → c11 → c10 → c6 → c4 → c1 → c0 → c3 → c5 → c9</p></details></div><h3>推理依据</h3><ul><li>墙 c1—c2 封闭该邻接</li></ul><p>关键分叉:第 2 步应走 c2,诱惑路线走 c7。排除依据:永久墙不能穿过。</p><details><summary>逐项机制必要性反例</summary><p>解除 wall:0 后:c8 → c7 → c2 → c1 → c0 → c3 → c4 → c6 → c5 → c9 → c10 → c11</p></details></article><article><h2>24 · 颜色接力 · 双色的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="双色的选择"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 327.5,122.5 225,122.5" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 225,122.5 225,225 122.5,225 122.5,327.5 20,327.5" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,122.5 327.5,122.5 327.5,225 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text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">11</text><text x="276.25" y="286.25" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text><text x="71.25" y="370.75" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">4</text><text x="71.25" y="388.75" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text><text x="173.75" y="370.75" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="173.75" y="388.75" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10</text></svg></figure><p>c4 → c7 → c10 → c9 → c6 → c3 → c0 → c1 → c2 → c5 → c8</p></details></div><h3>推理依据</h3><ul><li>c2 必须下与左拐角</li></ul><p>关键分叉:第 2 步应走 c7,诱惑路线走 c1。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c2 后:c4 → c1 → c0 → c3 → c6 → c9 → c10 → c7 → c8 → c5 → c2</p></details></article><article><h2>26 · 颜色接力 · 留下另一种颜色</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="留下另一种颜色"><polygon points="20,20 105,20 105,105 20,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 275,105 275,275 105,275" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,190 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→ c5 → c11</p></details></article><article><h2>27 · 颜色接力 · 双色 · 通道的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 295" role="img" aria-label="双色 · 通道的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 190,105 190,190 105,190 105,275 20,275" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,190 190,190 190,275 105,275" fill="#64acf3" stroke="#aaa1c7" 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→ c2 → c1 → c0 → c4 → c5</p></details></article><article><h2>28 · 颜色接力 · 短短的接力</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="短短的接力"><polygon points="20,20 105,20 105,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 275,105 275,275 105,275" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon 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font-weight="700">9</text><text x="147.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8 · ○</text><text x="62.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="62.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9 · └ △</text></svg></figure><p>c7 → c4 → c0 → c1 → c2 → c3 → c6 → c9 → c8 → c5</p></details></div><h3>推理依据</h3><ul><li>c2 必须左右直行</li><li>c9 必须上与右拐角</li><li>每步蓝橙交替</li></ul><p>关键分叉:第 6 步应走 c3,诱惑路线走 c5。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c2 后:c7 → c4 → c0 → c1 → c2 → c5 → c8 → c9 → c6 → c3</p><p>解除 direction:c9 后:c7 → c4 → c0 → c1 → c2 → c3 → c6 → c5 → c8 → c9</p><p>解除 alternation 后:c7 → c4 → c5 → c8 → c9 → c6 → c3 → c2 → c1 → c0</p></details></article><article><h2>31 · 安排奇偶 · 引导 · 偶数到达</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" 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font-family="system-ui" font-size="10" fill="#665c78">c9</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="偶数落脚"><polygon points="20,20 190,20 190,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,190 190,190 190,275 105,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,190 275,190 275,275 190,275" 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x="147.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6 · 偶</text><text x="232.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">5</text><text x="232.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">10</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text></svg></figure><p>c9 → c5 → c0 → c6 → c7 → c3 → c1 → c2 → c4 → c8</p></details></div><h3>推理依据</h3><ul><li>c6 为第4步,要求偶</li></ul><p>关键分叉:第 3 步应走 c0,诱惑路线走 c6。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c6 后:c9 → c5 → c6 → c0 → c1 → c3 → c7 → c8 → c4 → c2</p></details></article><article><h2>33 · 安排奇偶 · 奇偶 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="奇偶 · 墙的选择"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 327.5,20 327.5,122.5 225,122.5 225,225 122.5,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 122.5,122.5 122.5,225 20,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,122.5 327.5,122.5 327.5,225 225,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,225 122.5,225 122.5,327.5 20,327.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,225 225,225 225,327.5 122.5,327.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,225 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YaHei" font-size="21" font-weight="700">1</text><text x="276.25" y="388.75" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="奇偶 · 墙的选择"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 327.5,20 327.5,122.5 225,122.5 225,225 122.5,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 122.5,122.5 122.5,225 20,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,122.5 327.5,122.5 327.5,225 225,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,225 122.5,225 122.5,327.5 20,327.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,225 225,225 225,327.5 122.5,327.5" fill="#f1eef9" stroke="#aaa1c7" 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font-size="10" fill="#665c78">c11</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="奇数绕行"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 360,105 360,275 190,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#f1eef9" stroke="#aaa1c7" 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fill="#665c78">c9</text><text x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">4</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10</text><text x="232.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="232.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text></svg></figure><p>c3 → c6 → c11 → c10 → c9 → c7 → c8 → c5 → c4 → c0 → c1 → c2</p></details></div><h3>推理依据</h3><ul><li>c1 为第11步,要求奇</li></ul><p>关键分叉:第 3 步应走 c11,诱惑路线走 c2。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c1 后:c3 → c6 → c2 → c1 → c0 → c4 → c5 → c8 → c7 → c9 → c10 → c11</p></details></article><article><h2>35 · 安排奇偶 · 少量线索也够</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="少量线索也够"><polygon 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font-size="10" fill="#665c78">c11</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="少量线索也够"><polygon points="20,20 190,20 190,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,190 190,190 190,275 105,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,190 275,190 275,275 190,275" fill="#f1eef9" 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direction:c8 后:c3 → c1 → c0 → c2 → c4 → c7 → c8 → c5 → c6 → c9</p></details></article><article><h2>37 · 安排奇偶 · 回到双色小题</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="回到双色小题"><polygon points="20,20 105,20 105,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 275,20 275,105 190,105 190,190 105,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,190 190,190 190,275 105,275" 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font-weight="700"></text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="奇偶 · 通道的交错"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#f1eef9" 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font-size="21" font-weight="700">10</text><text x="147.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text><text x="232.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="232.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">12</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text></svg></figure><p>c3 → c7 → c10 → c6 → c2 → c1 → c0 → c4 → c5 → c9 → c8 → c11</p></details></div><h3>推理依据</h3><ul><li>c1 为第6步,要求偶</li><li>c8 必须右与下拐角</li></ul><p>关键分叉:第 2 步应走 c7,诱惑路线走 c2。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c1 后:c3 → c2 → c1 → c0 → c4 → c5 → c6 → c7 → c10 → c9 → c8 → c11</p><p>解除 direction:c8 后:c3 → c2 → c6 → c7 → c10 → c9 → c5 → c1 → c0 → c4 → c8 → c11</p></details></article><article><h2>39 · 安排奇偶 · 奇偶 · 墙的小径</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="奇偶 · 墙的小径"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 327.5,122.5 225,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 122.5,122.5 122.5,225 20,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,122.5 225,122.5 225,225 122.5,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,122.5 327.5,122.5 327.5,225 225,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,225 225,225 225,327.5 122.5,327.5 122.5,430 20,430" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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font-family="system-ui" font-size="10" fill="#665c78">c10 · └</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">7</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12</text></svg></figure><p>c12 → c8 → c9 → c5 → c6 → c10 → c11 → c7 → c3 → c2 → c1 → c0 → c4</p></details></div><h3>推理依据</h3><ul><li>c6 必须下与左拐角</li><li>c10 必须上与右拐角</li><li>墙 c4—c8 封闭该邻接</li></ul><p>关键分叉:第 5 步应走 c6,诱惑路线走 c4。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c6 后:c12 → c8 → c9 → c5 → c4 → c0 → c1 → c2 → c3 → c7 → c6 → c10 → c11</p><p>解除 direction:c10 后:c12 → c8 → c9 → c10 → c6 → c5 → c4 → c0 → c1 → c2 → c3 → c7 → c11</p><p>解除 wall:0 后:c12 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c11 → c10 → c6 → c5 → c9</p></details></article><article><h2>41 · 门的节奏 · 引导 · 门随步数切换</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="引导 · 门随步数切换"><polygon points="20,20 190,20 190,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 360,20 360,190 190,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 190,190 190,360 20,360" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,190 360,190 360,360 190,360" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><line x1="190" y1="210.4" x2="190" y2="339.6" stroke="#aa4d25" stroke-width="8" transform="rotate(0 190 275)"/><text x="198" y="267" font-size="12">步进门</text><text x="105" y="97" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="105" y="115" text-anchor="middle" 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fill="#665c78">c11</text></svg></figure><p>c5 → c8 → c9 → c6 → c3 → c2 → c1 → c0 → c4 → c7 → c11 → c10</p></details></div><h3>推理依据</h3><ul><li>c1 为第7步,要求奇</li><li>门 c11—c10 通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 2 步应走 c8,诱惑路线走 c4。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c1 后:c5 → c4 → c0 → c1 → c2 → c3 → c6 → c9 → c8 → c7 → c11 → c10</p><p>解除 door:0 后:c5 → c8 → c9 → c6 → c3 → c2 → c1 → c0 → c4 → c10 → c11 → c7</p></details></article><article><h2>43 · 门的节奏 · 门随脚步开关</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="门随脚步开关"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="门随脚步开关"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 133.33333333333331,133.33333333333331 133.33333333333331,246.66666666666666 20,246.66666666666666" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,133.33333333333331 246.66666666666666,133.33333333333331 246.66666666666666,246.66666666666666 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x="232.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6 · △</text><text x="317.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="317.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7 · ○</text><text x="62.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">11</text><text x="62.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8 · ○</text><text x="190" y="267" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">12</text><text x="190" y="285" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9 · △</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">2</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10 · △</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">13</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11 · ○</text><text x="317.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="317.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12 · ○</text></svg></figure><p>c12 → c10 → c7 → c3 → c2 → c6 → c5 → c1 → c0 → c4 → c8 → c9 → c11</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li></ul><p>关键分叉:第 6 步应走 c6,诱惑路线走 c1。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c12 → c10 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c6 → c9 → c8 → c11</p></details></article><article><h2>45 · 门的节奏 · 门 · 通道的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="门 · 通道的选择"><polygon points="20,20 190,20 190,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,190 190,190 190,275 105,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,190 275,190 275,275 190,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,190 360,190 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font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="317.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="147.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="147.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="232.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="232.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="317.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="317.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="62.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="62.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="147.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">7</text><text x="147.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text><text x="232.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">─</text><text x="232.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text 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font-weight="700">7</text><text x="147.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text><text x="232.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">6</text><text x="232.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8 · ─</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">5</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">9</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10</text><text x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11 · ┘</text></svg></figure><p>c2 → c1 → c4 → c5 → c9 → c8 → c7 → c11 → c10 → c6 → c0 → c3</p></details></div><h3>推理依据</h3><ul><li>c8 必须左右直行</li><li>c11 必须左与上拐角</li><li>门 c9—c8 通过前按已走格数切换,通过后保持开启;正确解从第5步末端通过</li></ul><p>关键分叉:第 3 步应走 c4,诱惑路线走 c0。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c8 后:c2 → c1 → c0 → c6 → c10 → c11 → c7 → c3 → c4 → c5 → c9 → c8</p><p>解除 direction:c11 后:c2 → c1 → c4 → c5 → c9 → c8 → c7 → c3 → c0 → c6 → c10 → c11</p><p>解除 door:0 后:c2 → c1 → c0 → c6 → c10 → c11 → c7 → c8 → c9 → c5 → c4 → c3</p></details></article><article><h2>46 · 门的节奏 · 直线与拐角</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="直线与拐角"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" 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x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">12</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13</text></svg></figure><p>c11 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c6 → c10 → c9 → c13 → c12 → c8</p></details></div><h3>推理依据</h3><ul><li>c0 必须右与下拐角</li><li>c5 必须左右直行</li><li>墙 c8—c9 封闭该邻接</li></ul><p>关键分叉:第 2 步应走 c7,诱惑路线走 c10。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c0 后:c11 → c10 → c9 → c13 → c12 → c8 → c4 → c5 → c6 → c7 → c3 → c2 → c1 → c0</p><p>解除 direction:c5 后:c11 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c12 → c13 → c9 → c5 → c6 → c10</p><p>解除 wall:0 后:c11 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c6 → c10 → c9 → c8 → c12 → c13</p></details></article><article><h2>47 · 门的节奏 · 从另一侧通过</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="从另一侧通过"><polygon points="20,20 122.5,20 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56.417478518114855,303.8461538461538 111.04369629528713,335.38461538461536 111.04369629528713,398.46153846153845 56.417478518114855,366.9230769230769" fill="none" stroke="#7963c9" stroke-width="5" opacity=".4"/><line x1="83.73058740670099" y1="368.853665855424" x2="83.73058740670099" y2="396.53094952919133" stroke="#aa4d25" stroke-width="8" transform="rotate(-149.99999999999997 83.73058740670099 382.6923076923077)"/><text x="91.73058740670099" y="374.6923076923077" font-size="12">步进门</text><text x="56.417478518114855" y="43.53846153846153" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">3</text><text x="56.417478518114855" y="61.53846153846153" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c0 · ○</text><text x="111.04369629528713" y="75.07692307692307" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">2</text><text x="111.04369629528713" y="93.07692307692307" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c1 · △</text><text x="56.417478518114855" y="106.61538461538461" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">4</text><text x="56.417478518114855" y="124.61538461538461" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2 · △</text><text x="111.04369629528713" y="138.15384615384613" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">1</text><text x="111.04369629528713" y="156.15384615384613" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3 · ○</text><text x="56.417478518114855" y="169.69230769230768" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">5</text><text x="56.417478518114855" y="187.69230769230768" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4 · ○</text><text x="111.04369629528713" 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font-family="system-ui" font-size="10" fill="#665c78">c11 · ○</text></svg></figure><p>c3 → c1 → c0 → c2 → c4 → c6 → c5 → c7 → c8 → c9 → c11 → c10</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>门 c11—c10 通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 6 步应走 c6,诱惑路线走 c5。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c3 → c1 → c0 → c2 → c4 → c5 → c6 → c7 → c8 → c9 → c10 → c11</p><p>解除 door:0 后:c3 → c1 → c0 → c2 → c4 → c6 → c5 → c7 → c8 → c10 → c11 → c9</p></details></article><article><h2>58 · 六向连接 · 顺着节拍收尾</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="顺着节拍收尾"><polygon points="20,20 102,20 102,102 20,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 102,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,20 266,20 266,102 184,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,20 348,20 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parity:c6 后:c8 → c4 → c2 → c1 → c3 → c7 → c6 → c0 → c5 → c9 → c13 → c14 → c10 → c11 → c12</p><p>解除 parity:c10 后:c8 → c12 → c11 → c10 → c14 → c13 → c9 → c5 → c0 → c6 → c7 → c3 → c1 → c2 → c4</p><p>解除 wall:0 后:c8 → c7 → c3 → c4 → c2 → c1 → c0 → c6 → c5 → c9 → c13 → c14 → c10 → c11 → c12</p><p>解除 wall:1 后:c8 → c12 → c11 → c7 → c3 → c4 → c2 → c1 → c0 → c6 → c5 → c9 → c10 → c14 → c13</p></details></article><article><h2>63 · 从哪里开始 · 奇偶 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="奇偶 · 墙 · 门的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 360,20 360,105 275,105 275,190 190,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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font-size="21" font-weight="700">○</text><text x="232.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="双色 · 墙的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 275,20 275,105 105,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 275,105 275,190 190,190 190,275 105,275" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 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c3</p></details></div><h3>推理依据</h3><ul><li>c2 必须左右直行</li><li>c9 必须左与上拐角</li><li>墙 c10—c11 封闭该邻接</li></ul><p>关键分叉:第 3 步应走 c6,诱惑路线走 c3。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c2 后:c11 → c7 → c3 → c2 → c6 → c10 → c14 → c13 → c12 → c8 → c9 → c5 → c1 → c0 → c4</p><p>解除 direction:c9 后:c11 → c7 → c6 → c5 → c9 → c10 → c14 → c13 → c12 → c8 → c4 → c0 → c1 → c2 → c3</p><p>解除 wall:0 后:c11 → c10 → c14 → c13 → c12 → c8 → c9 → c5 → c6 → c7 → c3 → c2 → c1 → c0 → c4</p></details></article><article><h2>68 · 从哪里开始 · 双色跨区</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="双色跨区"><polygon points="20,20 184,20 184,184 20,184" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,20 266,20 266,102 184,102" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,20 348,20 348,102 266,102" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,102 266,102 266,266 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c11 → c14 → c13</p></details></div><h3>推理依据</h3><ul><li>c12 为第10步,要求偶</li><li>墙 c4—c6 封闭该邻接</li></ul><p>关键分叉:第 7 步应走 c7,诱惑路线走 c8。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c12 后:c0 → c3 → c1 → c2 → c4 → c5 → c8 → c7 → c6 → c9 → c12 → c10 → c11 → c14 → c13</p><p>解除 wall:0 后:c0 → c3 → c1 → c2 → c4 → c6 → c9 → c12 → c10 → c7 → c5 → c8 → c11 → c14 → c13</p></details></article><article><h2>71 · 通道与颜色 · 颜色之外还有墙</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 237.26134197312211 450" role="img" aria-label="颜色之外还有墙"><polygon points="98.90453678924885,54.166666666666664 79.17840259193665,88.33333333333333 39.72613419731222,88.33333333333333 20,54.166666666666664 39.72613419731219,20.000000000000004 79.17840259193665,20" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="158.0829393811855,88.33333333333333 138.3568051838733,122.5 98.90453678924885,122.5 79.17840259193665,88.33333333333333 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c6 → c9 → c12 → c13 → c14 → c11 → c8 → c10</p><p>解除 wall:0 后:c7 → c5 → c8 → c11 → c14 → c13 → c12 → c10 → c9 → c6 → c3 → c0 → c1 → c2 → c4</p><p>解除 wall:1 后:c7 → c10 → c9 → c6 → c3 → c0 → c1 → c2 → c4 → c5 → c8 → c11 → c14 → c13 → c12</p></details></article><article><h2>72 · 通道与颜色 · 通道 · 双色 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 双色 · 墙 · 门的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,275 105,275 105,360 20,360" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#ffae55" 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△</text></svg></figure><p>c3 → c2 → c6 → c5 → c1 → c0 → c4 → c8 → c9 → c11 → c10 → c7</p></details></div><h3>推理依据</h3><ul><li>c2 必须右与下拐角</li><li>c4 必须左右直行</li><li>每步蓝橙交替</li><li>墙 c5—c9 封闭该邻接</li><li>门 c1—c0 通过前按已走格数切换,通过后保持开启;正确解从第5步末端通过</li></ul><p>关键分叉:第 3 步应走 c6,诱惑路线走 c1。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c2 后:c3 → c2 → c1 → c0 → c4 → c8 → c9 → c11 → c10 → c7 → c6 → c5</p><p>解除 direction:c4 后:c3 → c2 → c6 → c7 → c10 → c11 → c9 → c8 → c4 → c5 → c1 → c0</p><p>解除 alternation 后:c3 → c2 → c6 → c5 → c1 → c0 → c4 → c8 → c11 → c9 → c10 → c7</p><p>解除 wall:0 后:c3 → c2 → c6 → c7 → c10 → c11 → c9 → c5 → c1 → c0 → c4 → c8</p><p>解除 door:0 后:c3 → c2 → c6 → c7 → c10 → c11 → c9 → c8 → c4 → c0 → c1 → c5</p></details></article><article><h2>73 · 通道与颜色 · 两个双色枢纽</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="两个双色枢纽"><polygon points="20,20 102,20 102,184 20,184" fill="#ffae55" stroke="#aaa1c7" 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font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">4</text><text x="143" y="399" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c15 · △</text></svg></figure><p>c14 → c11 → c12 → c15 → c13 → c10 → c6 → c3 → c2 → c1 → c4 → c0 → c7 → c8 → c9 → c5</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c9—c10 封闭该邻接</li><li>墙 c4—c5 封闭该邻接</li></ul><p>关键分叉:第 2 步应走 c11,诱惑路线走 c15。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c14 → c15 → c13 → c10 → c6 → c3 → c2 → c5 → c9 → c8 → c4 → c1 → c0 → c7 → c11 → c12</p><p>解除 wall:0 后:c14 → c11 → c12 → c15 → c13 → c10 → c9 → c8 → c7 → c0 → c4 → c1 → c2 → c3 → c6 → c5</p><p>解除 wall:1 后:c14 → c11 → c12 → c15 → c13 → c10 → c6 → c3 → c2 → c1 → c4 → c5 → c9 → c8 → c7 → c0</p></details></article><article><h2>74 · 通道与颜色 · 起点没有写出</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 167.461174813402 450" role="img" aria-label="起点没有写出"><polygon 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8 步应走 c5,诱惑路线走 c10。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c5 后:c16 → c13 → c15 → c14 → c11 → c12 → c9 → c10 → c7 → c3 → c2 → c6 → c5 → c1 → c0 → c4 → c8</p><p>解除 parity:c7 后:c16 → c13 → c15 → c14 → c11 → c8 → c4 → c0 → c1 → c5 → c6 → c2 → c3 → c7 → c10 → c9 → c12</p><p>解除 wall:0 后:c16 → c13 → c15 → c14 → c11 → c12 → c9 → c8 → c4 → c0 → c1 → c5 → c6 → c10 → c7 → c3 → c2</p><p>解除 wall:1 后:c16 → c13 → c15 → c12 → c9 → c5 → c6 → c10 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c11 → c14</p></details></article><article><h2>78 · 通道与颜色 · 奇偶 · 墙 · 门的交错</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 150.4663515049484 450" role="img" aria-label="奇偶 · 墙 · 门的交错"><polygon points="83.12362943139908,47.33333333333333 67.34272207354931,74.66666666666666 35.78090735784978,74.66666666666666 20,47.333333333333336 35.780907357849756,20.000000000000004 67.34272207354931,20" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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font-weight="700">4</text><text x="59.452268394624426" y="405.8333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c15 · △</text></svg></figure><p>c6 → c9 → c12 → c15 → c13 → c14 → c11 → c8 → c10 → c7 → c5 → c2 → c1 → c4 → c3 → c0</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c6—c7 封闭该邻接</li><li>墙 c0—c1 封闭该邻接</li></ul><p>关键分叉:第 8 步应走 c8,诱惑路线走 c10。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c6 → c9 → c12 → c15 → c13 → c14 → c11 → c10 → c8 → c7 → c5 → c2 → c4 → c1 → c3 → c0</p><p>解除 wall:0 后:c6 → c7 → c10 → c9 → c12 → c15 → c13 → c14 → c11 → c8 → c5 → c2 → c1 → c4 → c3 → c0</p><p>解除 wall:1 后:c6 → c9 → c12 → c15 → c13 → c14 → c11 → c8 → c10 → c7 → c5 → c2 → c1 → c0 → c3 → c4</p></details></article><article><h2>80 · 通道与颜色 · 六边出口互锁</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 187.9460064798416 450" role="img" aria-label="六边出口互锁"><polygon points="79.17840259193665,45.625 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格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="双色 · 奇偶的选择"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 327.5,122.5 225,122.5" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 122.5,122.5 122.5,225 20,225" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,122.5 225,122.5 225,225 122.5,225" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,122.5 327.5,122.5 327.5,225 225,225" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,225 122.5,225 122.5,327.5 20,327.5" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,225 327.5,225 327.5,327.5 225,327.5 225,430 122.5,430" 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YaHei" font-size="11" font-weight="700">14</text><text x="111.04369629528713" y="282.30769230769226" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10</text><text x="165.66991407245942" y="295.8461538461538" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">8</text><text x="165.66991407245942" y="313.8461538461538" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text><text x="56.417478518114855" y="295.8461538461538" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">12</text><text x="56.417478518114855" y="313.8461538461538" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12 · 偶</text><text x="111.04369629528713" y="327.38461538461536" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">13</text><text x="111.04369629528713" y="345.38461538461536" text-anchor="middle" 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c14 → c16 → c15 → c12 → c13 → c10 → c9 → c6 → c4</p></details></div><h3>推理依据</h3><ul><li>c12 为第12步,要求偶</li><li>c14 为第9步,要求奇</li><li>墙 c8—c10 封闭该邻接</li><li>墙 c3—c6 封闭该邻接</li></ul><p>关键分叉:第 7 步应走 c8,诱惑路线走 c4。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c12 后:c0 → c3 → c1 → c2 → c5 → c7 → c4 → c6 → c9 → c10 → c12 → c15 → c13 → c16 → c14 → c11 → c8</p><p>解除 parity:c14 后:c0 → c3 → c1 → c2 → c4 → c7 → c5 → c8 → c11 → c14 → c16 → c15 → c13 → c12 → c10 → c9 → c6</p><p>解除 wall:0 后:c0 → c3 → c1 → c2 → c5 → c7 → c4 → c6 → c9 → c12 → c15 → c16 → c13 → c10 → c8 → c11 → c14</p><p>解除 wall:1 后:c0 → c3 → c6 → c9 → c10 → c7 → c4 → c1 → c2 → c5 → c8 → c11 → c13 → c12 → c15 → c16 → c14</p></details></article><article><h2>83 · 奇偶与门 · 方向决定门路</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="方向决定门路"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 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font-family="system-ui" font-size="10" fill="#665c78">c13</text><text x="232.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">14</text><text x="232.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c14</text><text x="317.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">13</text><text x="317.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c15</text></svg></figure><p>c10 → c9 → c8 → c4 → c0 → c1 → c5 → c6 → c2 → c3 → c7 → c11 → c15 → c14 → c13 → c12</p></details></div><h3>推理依据</h3><ul><li>c5 必须上与右拐角</li><li>c9 必须左右直行</li><li>门 c2—c3 通过前按已走格数切换,通过后保持开启;正确解从第9步末端通过</li></ul><p>关键分叉:第 4 步应走 c4,诱惑路线走 c12。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c5 后:c10 → c9 → c8 → c12 → c13 → c14 → c15 → c11 → c7 → c6 → c5 → c4 → c0 → c1 → c2 → c3</p><p>解除 direction:c9 后:c10 → c9 → c13 → c12 → c8 → c4 → c0 → c1 → c5 → c6 → c2 → c3 → c7 → c11 → c15 → c14</p><p>解除 door:0 后:c10 → c9 → c8 → c12 → c13 → c14 → c15 → c11 → c7 → c3 → c2 → c6 → c5 → c1 → c0 → c4</p></details></article><article><h2>84 · 奇偶与门 · 通道 · 奇偶 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 奇偶 · 墙 · 门的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 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c10。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c4 后:c5 → c6 → c8 → c10 → c11 → c12 → c9 → c7 → c3 → c2 → c1 → c0 → c4</p><p>解除 direction:c2 后:c5 → c6 → c2 → c1 → c0 → c4 → c8 → c10 → c11 → c12 → c9 → c7 → c3</p><p>解除 direction:c12 后:c5 → c6 → c11 → c10 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c9 → c12</p><p>解除 wall:0 后:c5 → c6 → c9 → c12 → c11 → c10 → c8 → c4 → c0 → c1 → c2 → c3 → c7</p><p>解除 door:0 后:c5 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c10 → c11 → c12 → c9</p></details></article><article><h2>85 · 奇偶与门 · 先定奇偶,再定节拍</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="先定奇偶,再定节拍"><polygon points="20,20 102,20 102,102 20,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 102,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,20 266,20 266,102 184,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,20 348,20 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c15 → c12 → c8</p></details></div><h3>推理依据</h3><ul><li>c4 为第3步,要求奇</li><li>c10 为第10步,要求偶</li><li>门 c3—c7 通过前按已走格数切换,通过后保持开启;正确解从第7步末端通过</li></ul><p>关键分叉:第 2 步应走 c5,诱惑路线走 c10。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c4 后:c9 → c10 → c6 → c5 → c1 → c2 → c3 → c7 → c11 → c14 → c13 → c16 → c15 → c12 → c8 → c4 → c0</p><p>解除 parity:c10 后:c9 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c11 → c14 → c16 → c15 → c12 → c13 → c10 → c6 → c5</p><p>解除 door:0 后:c9 → c8 → c12 → c15 → c16 → c14 → c11 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c6 → c10 → c13</p></details></article><article><h2>86 · 奇偶与门 · 墙通道门三者联动</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 312" role="img" aria-label="墙通道门三者联动"><polygon points="20,20 88,20 88,88 20,88" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,88 88,88 88,156 20,156" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,156 88,156 88,224 20,224" fill="#f1eef9" 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text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="19.72" font-weight="700">16</text><text x="326" y="64" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c16</text><text x="326" y="114" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="19.72" font-weight="700">17</text><text x="326" y="132" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c17</text></svg></figure><p>c11 → c15 → c14 → c10 → c9 → c5 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c12 → c16 → c17 → c13</p></details></div><h3>推理依据</h3><ul><li>c0 必须右与下拐角</li><li>c6 必须上下直行</li><li>c12 必须左右直行</li><li>墙 c1—c5 封闭该邻接</li><li>墙 c10—c11 封闭该邻接</li><li>门 c6—c7 通过前按已走格数切换,通过后保持开启;正确解从第7步末端通过</li></ul><p>关键分叉:第 6 步应走 c5,诱惑路线走 c13。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c0 后:c11 → c15 → c14 → c10 → c9 → c13 → c17 → c16 → c12 → c8 → c4 → c5 → c6 → c7 → c3 → c2 → c1 → c0</p><p>解除 direction:c6 后:c11 → c15 → c14 → c10 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c9 → c8 → c12 → c16 → c17 → c13</p><p>解除 direction:c12 后:c11 → c15 → c14 → c10 → c9 → c5 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c12 → c13 → c17 → c16</p><p>解除 wall:0 后:c11 → c15 → c14 → c10 → c9 → c13 → c17 → c16 → c12 → c8 → c4 → c0 → c1 → c5 → c6 → c7 → c3 → c2</p><p>解除 wall:1 后:c11 → c10 → c9 → c5 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c12 → c16 → c17 → c13 → c14 → c15</p><p>解除 door:0 后:c11 → c15 → c14 → c10 → c9 → c13 → c17 → c16 → c12 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c6 → c5</p></details></article><article><h2>87 · 奇偶与门 · 双色 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 158.35680518387326 450" role="img" aria-label="双色 · 墙 · 门的选择"><polygon points="87.63246010507044,49.28571428571428 70.72434507880283,78.57142857142856 36.908115026267616,78.57142857142856 20,49.285714285714285 36.908115026267595,20.000000000000004 70.72434507880283,20" fill="#64acf3" stroke="#aaa1c7" 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c0</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c3—c5 封闭该邻接</li><li>门 c3—c1 通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 10 步应走 c2,诱惑路线走 c3。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c10 → c12 → c11 → c9 → c8 → c7 → c6 → c5 → c4 → c3 → c2 → c0 → c1</p><p>解除 wall:0 后:c10 → c12 → c11 → c9 → c8 → c7 → c6 → c5 → c3 → c1 → c0 → c2 → c4</p><p>解除 door:0 后:c10 → c12 → c11 → c9 → c8 → c7 → c6 → c5 → c4 → c2 → c0 → c1 → c3</p></details></article><article><h2>88 · 奇偶与门 · 六边综合峰值</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 209.0811502626761 450" role="img" aria-label="六边综合峰值"><polygon points="87.63246010507044,49.28571428571428 70.72434507880283,78.57142857142856 36.908115026267616,78.57142857142856 20,49.285714285714285 36.908115026267595,20.000000000000004 70.72434507880283,20" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="138.35680518387326,78.57142857142856 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c1</p></details></div><h3>推理依据</h3><ul><li>c10 为第4步,要求偶</li><li>c18 为第8步,要求偶</li><li>墙 c10—c11 封闭该邻接</li><li>墙 c10—c13 封闭该邻接</li><li>门 c3—c0 通过前按已走格数切换,通过后保持开启;正确解从第17步末端通过</li></ul><p>关键分叉:第 3 步应走 c9,诱惑路线走 c10。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c10 后:c6 → c7 → c10 → c9 → c12 → c13 → c15 → c18 → c16 → c17 → c14 → c11 → c8 → c5 → c2 → c4 → c3 → c0 → c1</p><p>解除 parity:c18 后:c6 → c7 → c9 → c10 → c12 → c15 → c18 → c16 → c17 → c14 → c13 → c11 → c8 → c5 → c2 → c4 → c3 → c0 → c1</p><p>解除 wall:0 后:c6 → c7 → c9 → c12 → c15 → c18 → c16 → c17 → c14 → c13 → c11 → c10 → c8 → c5 → c2 → c4 → c3 → c0 → c1</p><p>解除 wall:1 后:c6 → c7 → c9 → c12 → c15 → c18 → c16 → c17 → c14 → c11 → c13 → c10 → c8 → c5 → c2 → c4 → c3 → c0 → c1</p><p>解除 door:0 后:c6 → c7 → c9 → c10 → c12 → c13 → c15 → c18 → c16 → c17 → c14 → c11 → c8 → c5 → c2 → c4 → c1 → c0 → c3</p></details></article><article><h2>89 · 奇偶与门 · 奇偶 · 墙 · 门的小径</h2><div class="boards"><figure><svg 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封闭该邻接</li><li>门 c4—c6 通过前按已走格数切换,通过后保持开启;正确解从第5步末端通过</li></ul><p>关键分叉:第 6 步应走 c6,诱惑路线走 c5。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c5 后:c0 → c2 → c1 → c3 → c4 → c5 → c6 → c7 → c8 → c10 → c9</p><p>解除 wall:0 后:c0 → c2 → c1 → c3 → c4 → c6 → c5 → c7 → c9 → c10 → c8</p><p>解除 door:0 后:c0 → c2 → c1 → c3 → c5 → c4 → c6 → c7 → c8 → c10 → c9</p></details></article><article><h2>90 · 奇偶与门 · 奇偶 · 墙的花园</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="奇偶 · 墙的花园"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 275,20 275,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 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fill="#665c78">c13</text></svg></figure><p>c1 → c0 → c2 → c4 → c3 → c5 → c6 → c7 → c9 → c8 → c10 → c12 → c13 → c11</p></details></div><h3>推理依据</h3><ul><li>c9 为第9步,要求奇</li><li>墙 c10—c11 封闭该邻接</li></ul><p>关键分叉:第 9 步应走 c9,诱惑路线走 c8。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c9 后:c1 → c0 → c2 → c4 → c3 → c5 → c6 → c7 → c8 → c9 → c10 → c12 → c13 → c11</p><p>解除 wall:0 后:c1 → c0 → c2 → c4 → c3 → c5 → c6 → c7 → c9 → c8 → c10 → c11 → c13 → c12</p></details></article><article><h2>92 · 区域与出口 · 通道 · 奇偶的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 奇偶的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 360,20 360,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" 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c1 → c7 → c8 → c4 → c2 → c5 → c9 → c13 → c12 → c11</p><p>解除 direction:c13 后:c10 → c6 → c3 → c0 → c1 → c7 → c11 → c12 → c8 → c4 → c2 → c5 → c9 → c13</p></details></article><article><h2>93 · 区域与出口 · 通道 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 墙 · 门的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#f1eef9" 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YaHei" font-size="21" font-weight="700">3</text><text x="62.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10 · ┌ ○</text><text x="232.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">6</text><text x="232.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11 · △</text><text x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">5</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12 · ○</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">4</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13 · △</text></svg></figure><p>c6 → c9 → c10 → c13 → c12 → c11 → c5 → c8 → c4 → c0 → c1 → c2 → c3 → c7</p></details></div><h3>推理依据</h3><ul><li>c10 必须右与下拐角</li><li>每步蓝橙交替</li><li>墙 c5—c9 封闭该邻接</li><li>门 c12—c11 通过前按已走格数切换,通过后保持开启;正确解从第5步末端通过</li></ul><p>关键分叉:第 3 步应走 c10,诱惑路线走 c12。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c10 后:c6 → c9 → c12 → c13 → c10 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c5 → c11</p><p>解除 alternation 后:c6 → c9 → c10 → c13 → c12 → c11 → c8 → c5 → c4 → c0 → c1 → c2 → c3 → c7</p><p>解除 wall:0 后:c6 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c5 → c9 → c10 → c13 → c12 → c11</p><p>解除 door:0 后:c6 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c5 → c11 → c12 → c9 → c10 → c13</p></details></article><article><h2>95 · 区域与出口 · 通道 · 奇偶 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 奇偶 · 墙 · 门的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" 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fill="#665c78">c13</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 奇偶 · 墙 · 门的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 275,105 275,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#f1eef9" stroke="#aaa1c7" 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parity:c7 后:c11 → c7 → c4 → c5 → c8 → c12 → c13 → c9 → c10 → c6 → c3 → c2 → c1 → c0</p><p>解除 direction:c10 后:c11 → c12 → c13 → c9 → c5 → c8 → c7 → c4 → c0 → c1 → c2 → c3 → c6 → c10</p><p>解除 wall:0 后:c11 → c12 → c13 → c9 → c10 → c6 → c5 → c8 → c7 → c4 → c0 → c1 → c2 → c3</p><p>解除 door:0 后:c11 → c12 → c13 → c9 → c10 → c6 → c3 → c2 → c5 → c1 → c0 → c4 → c7 → c8</p></details></article><article><h2>96 · 区域与出口 · 奇偶 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="奇偶 · 墙 · 门的选择"><polygon points="20,20 102,20 102,102 20,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 102,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,20 266,20 266,184 184,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,20 348,20 348,102 266,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,102 102,102 102,184 20,184" 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font-family="system-ui" font-size="10" fill="#665c78">c11</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">7</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12</text><text x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13</text></svg></figure><p>c3 → c2 → c1 → c0 → c4 → c8 → c12 → c13 → c9 → c5 → c6 → c10 → c11 → c7</p></details></div><h3>推理依据</h3><ul><li>c10 必须上与右拐角</li><li>墙 c2—c6 封闭该邻接</li></ul><p>关键分叉:第 12 步应走 c10,诱惑路线走 c7。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c10 后:c3 → c2 → c1 → c0 → c4 → c8 → c12 → c13 → c9 → c5 → c6 → c7 → c11 → c10</p><p>解除 wall:0 后:c3 → c7 → c11 → c10 → c6 → c2 → c1 → c0 → c4 → c5 → c9 → c8 → c12 → c13</p></details></article><article><h2>98 · 区域与出口 · 双色 · 墙 · 门的交错</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 137.47031015142505 450" role="img" aria-label="双色 · 墙 · 门的交错"><polygon points="75.6973200865286,44.11764705882353 61.772990064896454,68.23529411764706 33.92433002163216,68.23529411764706 20,44.117647058823536 33.92433002163214,20.000000000000004 61.772990064896454,20" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="117.47031015142505,68.23529411764706 103.54598012979291,92.3529411764706 75.6973200865286,92.3529411764706 61.772990064896454,68.23529411764706 75.69732008652859,44.117647058823536 103.54598012979291,44.11764705882353" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="75.6973200865286,92.3529411764706 61.772990064896454,116.47058823529412 33.92433002163216,116.47058823529412 20,92.3529411764706 33.92433002163214,68.23529411764706 61.772990064896454,68.23529411764706" fill="#ffae55" 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font-weight="700">6</text><text x="89.62165010816076" y="271.17647058823525" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9 · △</text><text x="47.8486600432643" y="277.29411764705884" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">7</text><text x="47.8486600432643" y="295.29411764705884" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10 · ○</text><text x="89.62165010816076" y="301.4117647058824" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">5</text><text x="89.62165010816076" y="319.4117647058824" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11 · ○</text><text x="47.8486600432643" y="325.5294117647059" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">1</text><text x="47.8486600432643" y="343.5294117647059" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12 · ○</text><text x="89.62165010816076" y="349.64705882352945" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">4</text><text x="89.62165010816076" y="367.64705882352945" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13 · △</text><text x="47.8486600432643" y="373.764705882353" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">2</text><text x="47.8486600432643" y="391.764705882353" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c14 · △</text><text x="89.62165010816076" y="397.88235294117646" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">3</text><text x="89.62165010816076" y="415.88235294117646" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c15 · ○</text></svg></figure><p>c12 → c14 → c15 → c13 → c11 → c9 → c10 → c8 → c7 → c6 → c4 → c2 → c0 → c1 → c3 → c5</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c4—c5 封闭该邻接</li><li>门 c0—c1 通过前按已走格数切换,通过后保持开启;正确解从第13步末端通过</li></ul><p>关键分叉:第 6 步应走 c9,诱惑路线走 c10。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c12 → c14 → c15 → c13 → c11 → c10 → c9 → c8 → c7 → c6 → c5 → c3 → c4 → c2 → c0 → c1</p><p>解除 wall:0 后:c12 → c14 → c15 → c13 → c11 → c9 → c10 → c8 → c7 → c6 → c4 → c5 → c3 → c2 → c0 → c1</p><p>解除 door:0 后:c12 → c14 → c15 → c13 → c11 → c9 → c10 → c8 → c7 → c5 → c3 → c1 → c0 → c2 → c4 → c6</p></details></article><article><h2>99 · 区域与出口 · 双色 · 墙的小径</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="双色 · 墙的小径"><polygon points="20,20 105,20 105,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#ffae55" stroke="#aaa1c7" 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y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="双色 · 墙的小径"><polygon points="20,20 105,20 105,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 190,105 190,190 105,190 105,275 20,275" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#ffae55" stroke="#aaa1c7" 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x="232.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">6</text><text x="232.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8 · △</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9 · ○</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">9</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10 · ○</text><text x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11 · △</text></svg></figure><p>c9 → c6 → c3 → c2 → c5 → c8 → c7 → c11 → c10 → c4 → c1 → c0</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c8—c9 封闭该邻接</li></ul><p>关键分叉:第 5 步应走 c5,诱惑路线走 c1。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c9 → c6 → c3 → c2 → c1 → c0 → c4 → c5 → c8 → c7 → c11 → c10</p><p>解除 wall:0 后:c9 → c8 → c7 → c11 → c10 → c4 → c5 → c6 → c3 → c2 → c1 → c0</p></details></article><article><h2>100 · 区域与出口 · 奇偶 · 墙 · 门的花园</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 255.19419124340598 450" role="img" aria-label="奇偶 · 墙 · 门的花园"><polygon points="235.19419124340598,392.7272727272727 213.67477211906538,430 170.63593387038418,430 149.11651474604358,392.7272727272727 170.63593387038415,355.45454545454544 213.67477211906538,355.45454545454544" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="170.63593387038418,355.45454545454544 149.11651474604358,392.7272727272727 106.07767649736239,392.7272727272727 84.55825737302179,355.45454545454544 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font-size="12.481263092117546" font-weight="700">14</text><text x="192.15535299472478" y="104.54545454545452" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12</text><text x="127.59709562170299" y="49.27272727272726" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="12.481263092117546" font-weight="700">12</text><text x="127.59709562170299" y="67.27272727272725" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13 · 偶</text></svg></figure><p>c4 → c2 → c1 → c0 → c3 → c6 → c9 → c7 → c5 → c8 → c11 → c13 → c10 → c12</p></details></div><h3>推理依据</h3><ul><li>c1 为第3步,要求奇</li><li>c13 为第12步,要求偶</li><li>墙 c4—c6 封闭该邻接</li><li>门 c9—c7 通过前按已走格数切换,通过后保持开启;正确解从第7步末端通过</li></ul><p>关键分叉:第 2 步应走 c2,诱惑路线走 c3。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c1 后:c4 → c3 → c0 → c1 → c2 → c5 → c8 → c7 → c6 → c9 → c12 → c13 → c10 → c11</p><p>解除 parity:c13 后:c4 → c2 → c1 → c0 → c3 → c6 → c7 → c5 → c8 → c11 → c13 → c12 → c10 → c9</p><p>解除 wall:0 后:c4 → c6 → c3 → c0 → c1 → c2 → c5 → c8 → c7 → c9 → c12 → c13 → c10 → c11</p><p>解除 door:0 后:c4 → c7 → c9 → c6 → c3 → c0 → c1 → c2 → c5 → c8 → c11 → c13 → c10 → c12</p></details></article><article><h2>101 · 交错规划 · 通道 · 双色的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 双色的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 275,20 275,105 105,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 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c11 → c10 → c8 → c9 → c7 → c6 → c5 → c3 → c4 → c2 → c1 → c0</p></details></div><h3>推理依据</h3><ul><li>c14 为第2步,要求偶</li><li>墙 c9—c11 封闭该邻接</li></ul><p>关键分叉:第 1 步应走 c13,诱惑路线走 c14。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c14 后:c14 → c13 → c12 → c11 → c10 → c8 → c9 → c7 → c6 → c5 → c3 → c4 → c2 → c1 → c0</p><p>解除 wall:0 后:c8 → c10 → c12 → c14 → c13 → c11 → c9 → c7 → c6 → c5 → c3 → c4 → c2 → c1 → c0</p></details></article><article><h2>103 · 交错规划 · 通道 · 奇偶的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 奇偶的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" 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c12</p></details></div><h3>推理依据</h3><ul><li>c11 必须左与上拐角</li><li>墙 c9—c13 封闭该邻接</li><li>墙 c4—c5 封闭该邻接</li><li>门 c3—c7 通过前按已走格数切换,通过后保持开启;正确解从第9步末端通过</li></ul><p>关键分叉:第 4 步应走 c8,诱惑路线走 c10。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c11 后:c6 → c5 → c9 → c10 → c14 → c13 → c12 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c11</p><p>解除 wall:0 后:c6 → c5 → c9 → c13 → c12 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c11 → c10 → c14</p><p>解除 wall:1 后:c6 → c5 → c4 → c0 → c1 → c2 → c3 → c7 → c11 → c10 → c14 → c13 → c12 → c8 → c9</p><p>解除 door:0 后:c6 → c5 → c9 → c8 → c12 → c13 → c14 → c10 → c11 → c7 → c3 → c2 → c1 → c0 → c4</p></details></article><article><h2>105 · 交错规划 · 通道 · 双色 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 双色 · 墙 · 门的选择"><polygon points="275,20 360,20 360,105 275,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#ffae55" 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通过前按已走格数切换,通过后保持开启;正确解从第9步末端通过</li></ul><p>关键分叉:第 2 步应走 c3,诱惑路线走 c1。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c1 后:c0 → c1 → c4 → c5 → c2 → c6 → c13 → c12 → c9 → c8 → c11 → c10 → c7 → c3</p><p>解除 alternation 后:c0 → c3 → c4 → c1 → c2 → c5 → c6 → c13 → c12 → c9 → c8 → c7 → c10 → c11</p><p>解除 wall:0 后:c0 → c3 → c4 → c1 → c2 → c5 → c9 → c6 → c13 → c12 → c11 → c8 → c7 → c10</p><p>解除 door:0 后:c0 → c3 → c4 → c1 → c2 → c5 → c9 → c8 → c7 → c10 → c11 → c12 → c13 → c6</p></details></article><article><h2>106 · 交错规划 · 通道 · 奇偶 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 奇偶 · 墙 · 门的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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c11 → c8 → c4 → c0 → c1 → c5 → c9</p><p>解除 door:0 后:c3 → c2 → c6 → c10 → c7 → c13 → c12 → c11 → c8 → c9 → c5 → c4 → c0 → c1</p></details></article><article><h2>107 · 交错规划 · 奇偶 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="奇偶 · 墙 · 门的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#f1eef9" stroke="#aaa1c7" 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通过前按已走格数切换,通过后保持开启;正确解从第13步末端通过</li></ul><p>关键分叉:第 4 步应走 c13,诱惑路线走 c6。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c1 后:c14 → c11 → c10 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c9 → c8 → c12 → c13</p><p>解除 wall:0 后:c14 → c11 → c10 → c13 → c12 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c6 → c5 → c9</p><p>解除 door:0 后:c14 → c11 → c10 → c13 → c12 → c8 → c9 → c5 → c4 → c0 → c1 → c2 → c6 → c7 → c3</p></details></article><article><h2>108 · 交错规划 · 通道 · 墙的交错</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="通道 · 墙的交错"><polygon points="20,20 102,20 102,102 20,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 102,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,20 266,20 266,102 184,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,20 348,20 348,102 266,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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→ c10 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c9 → c5</p></details></article><article><h2>109 · 交错规划 · 双色 · 墙 · 门的小径</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 158.35680518387326 450" role="img" aria-label="双色 · 墙 · 门的小径"><polygon points="87.63246010507044,49.28571428571428 70.72434507880283,78.57142857142856 36.908115026267616,78.57142857142856 20,49.285714285714285 36.908115026267595,20.000000000000004 70.72434507880283,20" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="138.35680518387326,78.57142857142856 121.44869015760565,107.85714285714285 87.63246010507044,107.85714285714285 70.72434507880283,78.57142857142856 87.63246010507042,49.285714285714285 121.44869015760565,49.28571428571428" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="87.63246010507044,107.85714285714285 70.72434507880283,137.1428571428571 36.908115026267616,137.1428571428571 20,107.85714285714285 36.908115026267595,78.57142857142856 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双色 · 墙的花园</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="双色 · 墙的花园"><polygon points="20,20 102,20 102,102 20,102" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 102,102" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,20 266,20 266,102 184,102" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,20 348,20 348,184 266,184" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,102 102,102 102,184 20,184" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,102 184,102 184,184 102,184" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,102 266,102 266,184 184,184" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,184 102,184 102,266 20,266" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,184 184,184 184,266 102,266" fill="#ffae55" 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fill="#665c78">c14 · ○</text></svg></figure><p>c14 → c11 → c12 → c9 → c13 → c10 → c3 → c6 → c2 → c1 → c0 → c4 → c5 → c8 → c7</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c1—c5 封闭该邻接</li></ul><p>关键分叉:第 3 步应走 c12,诱惑路线走 c7。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c14 → c11 → c7 → c4 → c0 → c1 → c2 → c3 → c10 → c13 → c9 → c6 → c5 → c8 → c12</p><p>解除 wall:0 后:c14 → c11 → c7 → c8 → c12 → c9 → c13 → c10 → c3 → c6 → c2 → c1 → c5 → c4 → c0</p></details></article><article><h2>111 · 多线索协作 · 双色 · 奇偶的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="双色 · 奇偶的选择"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 327.5,122.5 225,122.5" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon 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font-weight="700">3</text><text x="173.75" y="388.75" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9 · ○</text></svg></figure><p>c4 → c6 → c9 → c8 → c3 → c0 → c1 → c2 → c5 → c7</p></details></div><h3>推理依据</h3><ul><li>c4 为第1步,要求奇</li><li>每步蓝橙交替</li></ul><p>关键分叉:第 1 步应走 c4,诱惑路线走 c7。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c4 后:c7 → c5 → c2 → c1 → c0 → c3 → c8 → c9 → c6 → c4</p><p>解除 alternation 后:c0 → c1 → c2 → c5 → c7 → c6 → c4 → c3 → c8 → c9</p></details></article><article><h2>112 · 多线索协作 · 通道 · 双色的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 双色的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon 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direction:c2 后:c10 → c11 → c8 → c4 → c0 → c1 → c5 → c6 → c2 → c3 → c7 → c9</p><p>解除 direction:c11 后:c10 → c8 → c5 → c4 → c0 → c1 → c2 → c3 → c7 → c6 → c9 → c11</p></details></article><article><h2>115 · 多线索协作 · 通道 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="通道 · 墙 · 门的选择"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 327.5,122.5 225,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 122.5,122.5 122.5,225 20,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,122.5 225,122.5 225,225 122.5,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,122.5 327.5,122.5 327.5,225 225,225" fill="#f1eef9" stroke="#aaa1c7" 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font-family="system-ui" font-size="10" fill="#665c78">c13</text></svg></figure><p>c11 → c12 → c13 → c10 → c9 → c5 → c6 → c3 → c2 → c1 → c0 → c4 → c7 → c8</p></details></div><h3>推理依据</h3><ul><li>c10 为第4步,要求偶</li><li>c6 必须左与上拐角</li><li>墙 c1—c8 封闭该邻接</li><li>门 c0—c4 通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 3 步应走 c13,诱惑路线走 c8。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c10 后:c11 → c12 → c8 → c7 → c4 → c0 → c1 → c2 → c3 → c6 → c5 → c9 → c10 → c13</p><p>解除 direction:c6 后:c11 → c12 → c13 → c10 → c6 → c3 → c2 → c5 → c9 → c8 → c7 → c4 → c1 → c0</p><p>解除 wall:0 后:c11 → c12 → c13 → c10 → c9 → c5 → c6 → c3 → c2 → c1 → c8 → c7 → c4 → c0</p><p>解除 door:0 后:c11 → c12 → c13 → c10 → c9 → c8 → c7 → c4 → c0 → c1 → c2 → c3 → c6 → c5</p></details></article><article><h2>118 · 多线索协作 · 奇偶 · 墙 · 门的交错</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="奇偶 · 墙 · 门的交错"><polygon points="20,20 105,20 105,105 20,105" 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通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 7 步应走 c5,诱惑路线走 c9。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c12 后:c1 → c0 → c4 → c7 → c11 → c8 → c9 → c5 → c2 → c3 → c6 → c10 → c13 → c12</p><p>解除 wall:0 后:c1 → c0 → c4 → c7 → c11 → c8 → c12 → c13 → c10 → c9 → c5 → c2 → c3 → c6</p><p>解除 door:0 后:c1 → c0 → c4 → c7 → c11 → c8 → c5 → c2 → c3 → c6 → c10 → c9 → c12 → c13</p></details></article><article><h2>119 · 多线索协作 · 通道 · 墙的小径</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="通道 · 墙的小径"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 327.5,122.5 225,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 122.5,122.5 122.5,225 20,225" fill="#f1eef9" stroke="#aaa1c7" 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font-weight="700">1</text><text x="177.8090735784977" y="405.8333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11 · ○</text></svg></figure><p>c11 → c8 → c5 → c2 → c4 → c1 → c0 → c3 → c6 → c7 → c10 → c9</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c5—c7 封闭该邻接</li><li>墙 c4—c7 封闭该邻接</li><li>门 c10—c9 通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 11 步应走 c10,诱惑路线走 c9。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c11 → c8 → c5 → c2 → c4 → c1 → c0 → c3 → c6 → c7 → c9 → c10</p><p>解除 wall:0 后:c11 → c8 → c5 → c7 → c10 → c9 → c6 → c3 → c0 → c1 → c4 → c2</p><p>解除 wall:1 后:c11 → c8 → c5 → c2 → c4 → c7 → c10 → c9 → c6 → c3 → c0 → c1</p><p>解除 door:0 后:c11 → c8 → c5 → c2 → c4 → c1 → c0 → c3 → c6 → c9 → c10 → c7</p></details></article><article><h2>121 · 方向与节拍 · 奇偶 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="奇偶 · 墙的选择"><polygon 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font-family="system-ui" font-size="10" fill="#665c78">c1</text><text x="317.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="317.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="62.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="62.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="147.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="147.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="232.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">奇</text><text x="232.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="317.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="317.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="62.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">4</text><text x="62.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text><text x="147.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="147.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text><text x="232.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="232.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text><text x="317.5" y="224.5" 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c1—c4 封闭该邻接</li></ul><p>关键分叉:第 6 步应走 c4,诱惑路线走 c0。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c5 后:c11 → c12 → c8 → c7 → c3 → c0 → c1 → c2 → c6 → c10 → c9 → c5 → c4</p><p>解除 wall:0 后:c11 → c12 → c8 → c7 → c3 → c0 → c1 → c4 → c5 → c9 → c10 → c6 → c2</p></details></article><article><h2>122 · 方向与节拍 · 双色 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 158.35680518387326 450" role="img" aria-label="双色 · 墙的选择"><polygon points="87.63246010507044,49.28571428571428 70.72434507880283,78.57142857142856 36.908115026267616,78.57142857142856 20,49.285714285714285 36.908115026267595,20.000000000000004 70.72434507880283,20" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="138.35680518387326,78.57142857142856 121.44869015760565,107.85714285714285 87.63246010507044,107.85714285714285 70.72434507880283,78.57142857142856 87.63246010507042,49.285714285714285 121.44869015760565,49.28571428571428" fill="#ffae55" 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○</text></svg></figure><p>c12 → c10 → c11 → c9 → c8 → c6 → c7 → c5 → c4 → c2 → c3 → c1 → c0</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c0—c2 封闭该邻接</li></ul><p>关键分叉:第 2 步应走 c10,诱惑路线走 c11。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c12 → c11 → c10 → c9 → c8 → c7 → c6 → c5 → c4 → c3 → c2 → c1 → c0</p><p>解除 wall:0 后:c12 → c10 → c11 → c9 → c8 → c6 → c7 → c5 → c4 → c2 → c0 → c1 → c3</p></details></article><article><h2>123 · 方向与节拍 · 通道 · 双色的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 双色的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#ffae55" stroke="#aaa1c7" 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x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">13</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12</text></svg></figure><p>c10 → c9 → c8 → c5 → c6 → c3 → c2 → c1 → c0 → c4 → c7 → c11 → c12</p></details></div><h3>推理依据</h3><ul><li>c4 为第10步,要求偶</li><li>c0 必须右与下拐角</li></ul><p>关键分叉:第 2 步应走 c9,诱惑路线走 c6。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c4 后:c10 → c6 → c3 → c2 → c1 → c0 → c4 → c5 → c9 → c8 → c7 → c11 → c12</p><p>解除 direction:c0 后:c10 → c6 → c3 → c2 → c1 → c5 → c9 → c8 → c12 → c11 → c7 → c4 → c0</p></details></article><article><h2>126 · 方向与节拍 · 通道 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 墙 · 门的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" 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c1</p></details></div><h3>推理依据</h3><ul><li>c4 必须上与右拐角</li><li>c10 必须左右直行</li><li>墙 c6—c7 封闭该邻接</li><li>门 c4—c0 通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 3 步应走 c9,诱惑路线走 c4。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c4 后:c12 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c11 → c10 → c9 → c5 → c6</p><p>解除 direction:c10 后:c12 → c8 → c9 → c10 → c6 → c5 → c4 → c0 → c1 → c2 → c3 → c7 → c11</p><p>解除 wall:0 后:c12 → c8 → c9 → c10 → c11 → c7 → c6 → c5 → c4 → c0 → c1 → c2 → c3</p><p>解除 door:0 后:c12 → c8 → c9 → c10 → c11 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c6</p></details></article><article><h2>127 · 方向与节拍 · 通道 · 双色 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 双色 · 墙 · 门的选择"><polygon points="20,20 190,20 190,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon 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c7 → c8 → c5 → c9 → c13 → c12 → c11 → c10 → c6</p></details></div><h3>推理依据</h3><ul><li>c0 为第3步,要求奇</li><li>c13 为第10步,要求偶</li><li>c13 必须上与右拐角</li><li>墙 c6—c7 封闭该邻接</li><li>墙 c7—c11 封闭该邻接</li><li>门 c8—c5 通过前按已走格数切换,通过后保持开启;正确解从第7步末端通过</li></ul><p>关键分叉:第 3 步应走 c0,诱惑路线走 c5。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c0 后:c2 → c1 → c5 → c4 → c7 → c8 → c9 → c13 → c12 → c11 → c10 → c6 → c3 → c0</p><p>解除 parity:c13 后:c2 → c1 → c0 → c3 → c6 → c10 → c11 → c12 → c13 → c9 → c5 → c4 → c7 → c8</p><p>解除 direction:c13 后:c2 → c1 → c0 → c3 → c6 → c10 → c11 → c12 → c8 → c7 → c4 → c5 → c9 → c13</p><p>解除 wall:0 后:c2 → c1 → c0 → c3 → c4 → c5 → c9 → c13 → c12 → c8 → c7 → c6 → c10 → c11</p><p>解除 wall:1 后:c2 → c1 → c0 → c3 → c4 → c5 → c9 → c13 → c12 → c8 → c7 → c11 → c10 → c6</p><p>解除 door:0 后:c2 → c1 → c0 → c4 → c3 → c6 → c10 → c11 → c12 → c13 → c9 → c5 → c8 → c7</p></details></article><article><h2>129 · 方向与节拍 · 奇偶 · 墙 · 门的小径</h2><div class="boards"><figure><svg 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x="147.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c1</text><text x="232.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="232.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="317.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="317.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="62.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="62.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="147.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="147.5" y="157.5" text-anchor="middle" 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→ c10 → c9 → c8 → c4 → c0 → c1</p></details></div><h3>推理依据</h3><ul><li>c9 为第7步,要求奇</li><li>墙 c6—c7 封闭该邻接</li><li>门 c7—c10 通过前按已走格数切换,通过后保持开启;正确解从第5步末端通过</li></ul><p>关键分叉:第 2 步应走 c6,诱惑路线走 c1。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c9 后:c5 → c1 → c0 → c4 → c8 → c9 → c10 → c7 → c3 → c2 → c6</p><p>解除 wall:0 后:c5 → c6 → c7 → c10 → c9 → c8 → c4 → c0 → c1 → c2 → c3</p><p>解除 door:0 后:c5 → c6 → c9 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c10</p></details></article><article><h2>130 · 方向与节拍 · 通道 · 墙的花园</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 墙的花园"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" 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fill="#665c78">c13</text></svg></figure><p>c5 → c1 → c0 → c4 → c7 → c8 → c10 → c12 → c13 → c11 → c9 → c6 → c2 → c3</p></details></div><h3>推理依据</h3><ul><li>c2 为第13步,要求奇</li><li>c7 为第5步,要求奇</li><li>墙 c5—c8 封闭该邻接</li><li>墙 c5—c6 封闭该邻接</li></ul><p>关键分叉:第 13 步应走 c2,诱惑路线走 c3。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c2 后:c5 → c1 → c0 → c4 → c7 → c8 → c10 → c12 → c13 → c11 → c9 → c6 → c3 → c2</p><p>解除 parity:c7 后:c5 → c1 → c2 → c3 → c6 → c9 → c11 → c13 → c12 → c10 → c8 → c7 → c4 → c0</p><p>解除 wall:0 后:c5 → c8 → c7 → c4 → c0 → c1 → c2 → c3 → c6 → c9 → c11 → c10 → c12 → c13</p><p>解除 wall:1 后:c5 → c6 → c9 → c11 → c13 → c12 → c10 → c8 → c7 → c4 → c0 → c1 → c2 → c3</p></details></article><article><h2>133 · 跨区的选择 · 双色 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 150.4663515049484 450" role="img" aria-label="双色 · 墙的选择"><polygon points="83.12362943139908,47.33333333333333 67.34272207354931,74.66666666666666 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c11</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c10—c11 封闭该邻接</li></ul><p>关键分叉:第 13 步应走 c13,诱惑路线走 c11。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c6 → c4 → c2 → c0 → c1 → c3 → c5 → c7 → c8 → c9 → c10 → c12 → c11 → c13</p><p>解除 wall:0 后:c6 → c4 → c2 → c0 → c1 → c3 → c5 → c7 → c8 → c9 → c10 → c11 → c13 → c12</p></details></article><article><h2>134 · 跨区的选择 · 通道 · 双色的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 双色的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#64acf3" 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font-size="21" font-weight="700">1</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11 · 奇</text><text x="190" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">7</text><text x="190" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12</text><text x="317.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="317.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13</text></svg></figure><p>c11 → c7 → c4 → c0 → c1 → c8 → c12 → c13 → c10 → c9 → c5 → c6 → c3 → c2</p></details></div><h3>推理依据</h3><ul><li>c0 为第4步,要求偶</li><li>c11 为第1步,要求奇</li><li>c10 必须下与左拐角</li></ul><p>关键分叉:第 2 步应走 c7,诱惑路线走 c12。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c0 后:c11 → c12 → c13 → c10 → c9 → c8 → c7 → c4 → c0 → c1 → c5 → c6 → c3 → c2</p><p>解除 parity:c11 后:c4 → c0 → c1 → c8 → c7 → c11 → c12 → c13 → c10 → c9 → c5 → c6 → c3 → c2</p><p>解除 direction:c10 后:c1 → c0 → c4 → c7 → c11 → c12 → c8 → c9 → c5 → c2 → c3 → c6 → c10 → c13</p></details></article><article><h2>137 · 跨区的选择 · 通道 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 墙 · 门的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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font-size="21" font-weight="700">13</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13</text></svg></figure><p>c0 → c1 → c2 → c3 → c7 → c11 → c10 → c6 → c5 → c4 → c8 → c12 → c13 → c9</p></details></div><h3>推理依据</h3><ul><li>c4 必须右与下拐角</li><li>墙 c8—c9 封闭该邻接</li><li>门 c5—c4 通过前按已走格数切换,通过后保持开启;正确解从第9步末端通过</li></ul><p>关键分叉:第 10 步应走 c4,诱惑路线走 c9。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c4 后:c0 → c1 → c2 → c3 → c7 → c11 → c10 → c6 → c5 → c9 → c13 → c12 → c8 → c4</p><p>解除 wall:0 后:c0 → c1 → c2 → c3 → c7 → c11 → c10 → c6 → c5 → c4 → c8 → c9 → c13 → c12</p><p>解除 door:0 后:c0 → c1 → c2 → c3 → c7 → c11 → c10 → c9 → c13 → c12 → c8 → c4 → c5 → c6</p></details></article><article><h2>138 · 跨区的选择 · 通道 · 双色 · 墙 · 门的交错</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 双色 · 墙 · 门的交错"><polygon points="275,20 360,20 360,105 275,105" fill="#64acf3" 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通过前按已走格数切换,通过后保持开启;正确解从第9步末端通过</li></ul><p>关键分叉:第 3 步应走 c5,诱惑路线走 c2。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c3 后:c0 → c1 → c2 → c6 → c5 → c8 → c4 → c11 → c12 → c9 → c13 → c10 → c7 → c3</p><p>解除 alternation 后:c0 → c1 → c5 → c4 → c11 → c12 → c8 → c9 → c13 → c10 → c7 → c3 → c2 → c6</p><p>解除 wall:0 后:c0 → c1 → c2 → c3 → c7 → c6 → c5 → c8 → c4 → c11 → c12 → c9 → c13 → c10</p><p>解除 door:0 后:c0 → c1 → c2 → c3 → c7 → c10 → c13 → c9 → c12 → c11 → c4 → c8 → c5 → c6</p></details></article><article><h2>139 · 跨区的选择 · 通道 · 奇偶 · 墙 · 门的小径</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 奇偶 · 墙 · 门的小径"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">2</text><text x="317.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13</text></svg></figure><p>c11 → c12 → c13 → c10 → c9 → c6 → c3 → c2 → c1 → c0 → c4 → c7 → c8 → c5</p></details></div><h3>推理依据</h3><ul><li>c10 为第4步,要求偶</li><li>c8 必须左与上拐角</li><li>墙 c4—c5 封闭该邻接</li><li>门 c4—c7 通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 4 步应走 c10,诱惑路线走 c9。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c10 后:c11 → c12 → c13 → c9 → c10 → c3 → c6 → c2 → c1 → c0 → c4 → c7 → c8 → c5</p><p>解除 direction:c8 后:c11 → c12 → c8 → c9 → c13 → c10 → c3 → c2 → c6 → c5 → c1 → c0 → c4 → c7</p><p>解除 wall:0 后:c11 → c7 → c8 → c5 → c4 → c0 → c1 → c2 → c3 → c6 → c9 → c10 → c13 → c12</p><p>解除 door:0 后:c11 → c12 → c13 → c10 → c9 → c6 → c3 → c2 → c1 → c5 → c8 → c7 → c4 → c0</p></details></article><article><h2>140 · 跨区的选择 · 奇偶 · 墙 · 门的花园</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="奇偶 · 墙 · 门的花园"><polygon points="190,20 360,20 360,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,275 20,275" 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门的花园"><polygon points="190,20 360,20 360,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,275 20,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,190 360,190 360,275 275,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,190 275,190 275,275 190,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,190 190,190 190,275 105,275" fill="#f1eef9" stroke="#aaa1c7" 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通过前按已走格数切换,通过后保持开启;正确解从第13步末端通过</li></ul><p>关键分叉:第 2 步应走 c1,诱惑路线走 c6。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c7 后:c2 → c6 → c13 → c12 → c11 → c10 → c7 → c8 → c4 → c3 → c0 → c1 → c5 → c9</p><p>解除 parity:c9 后:c2 → c6 → c13 → c12 → c9 → c5 → c1 → c0 → c3 → c4 → c8 → c7 → c10 → c11</p><p>解除 wall:0 后:c2 → c1 → c0 → c3 → c4 → c5 → c6 → c9 → c8 → c7 → c10 → c11 → c12 → c13</p><p>解除 wall:1 后:c2 → c1 → c0 → c4 → c3 → c7 → c10 → c11 → c8 → c9 → c5 → c6 → c13 → c12</p><p>解除 door:0 后:c2 → c1 → c0 → c3 → c4 → c5 → c6 → c13 → c12 → c9 → c8 → c11 → c10 → c7</p></details></article><article><h2>141 · 留住通路 · 双色 · 奇偶 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="双色 · 奇偶 · 墙的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 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封闭该邻接</li><li>门 c14—c12 通过前按已走格数切换,通过后保持开启;正确解从第13步末端通过</li></ul><p>关键分叉:第 6 步应走 c6,诱惑路线走 c5。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c7 后:c0 → c2 → c1 → c3 → c4 → c5 → c6 → c8 → c7 → c9 → c11 → c13 → c14 → c12 → c10</p><p>解除 wall:0 后:c0 → c2 → c1 → c3 → c4 → c5 → c6 → c7 → c8 → c9 → c11 → c13 → c14 → c12 → c10</p><p>解除 door:0 后:c0 → c2 → c1 → c3 → c4 → c6 → c5 → c7 → c8 → c9 → c10 → c12 → c14 → c13 → c11</p></details></article><article><h2>143 · 留住通路 · 奇偶 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="奇偶 · 墙的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" 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font-size="10" fill="#665c78">c11 · 奇</text><text x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">6</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12</text><text x="232.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="232.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13</text><text x="317.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">2</text><text x="317.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c14</text></svg></figure><p>c13 → c14 → c7 → c10 → c9 → c12 → c11 → c8 → c4 → c0 → c1 → c5 → c6 → c2 → c3</p></details></div><h3>推理依据</h3><ul><li>c11 为第7步,要求奇</li><li>墙 c5—c9 封闭该邻接</li></ul><p>关键分叉:第 4 步应走 c10,诱惑路线走 c3。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c11 后:c13 → c14 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c6 → c10 → c9 → c8 → c11 → c12</p><p>解除 wall:0 后:c13 → c14 → c7 → c10 → c6 → c5 → c9 → c12 → c11 → c8 → c4 → c0 → c1 → c2 → c3</p></details></article><article><h2>144 · 留住通路 · 双色 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 209.0811502626761 450" role="img" aria-label="双色 · 墙的选择"><polygon points="87.63246010507044,49.28571428571428 70.72434507880283,78.57142857142856 36.908115026267616,78.57142857142856 20,49.285714285714285 36.908115026267595,20.000000000000004 70.72434507880283,20" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="138.35680518387326,78.57142857142856 121.44869015760565,107.85714285714285 87.63246010507044,107.85714285714285 70.72434507880283,78.57142857142856 87.63246010507042,49.285714285714285 121.44869015760565,49.28571428571428" fill="#64acf3" stroke="#aaa1c7" 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font-weight="700">3</text><text x="104.54057513133804" y="322.8571428571428" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13 · ○</text><text x="155.26492021014087" y="392.71428571428567" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">1</text><text x="155.26492021014087" y="410.71428571428567" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c14 · ○</text></svg></figure><p>c14 → c11 → c13 → c12 → c10 → c8 → c5 → c2 → c4 → c7 → c9 → c6 → c3 → c0 → c1</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c4—c6 封闭该邻接</li><li>墙 c7—c10 封闭该邻接</li></ul><p>关键分叉:第 3 步应走 c13,诱惑路线走 c8。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c14 → c11 → c8 → c13 → c12 → c9 → c10 → c5 → c2 → c7 → c6 → c3 → c0 → c1 → c4</p><p>解除 wall:0 后:c14 → c11 → c13 → c8 → c10 → c12 → c9 → c7 → c5 → c2 → c4 → c6 → c3 → c0 → c1</p><p>解除 wall:1 后:c14 → c11 → c13 → c8 → c5 → c2 → c4 → c7 → c10 → c12 → c9 → c6 → c3 → c0 → c1</p></details></article><article><h2>145 · 留住通路 · 通道 · 双色的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 双色的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,275 20,275" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#64acf3" stroke="#aaa1c7" 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c14 → c13 → c9 → c8 → c12</p></details></div><h3>推理依据</h3><ul><li>c13 必须上与右拐角</li><li>每步蓝橙交替</li></ul><p>关键分叉:第 13 步应走 c9,诱惑路线走 c12。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c13 后:c11 → c4 → c0 → c1 → c5 → c6 → c2 → c3 → c7 → c10 → c14 → c13 → c12 → c8 → c9</p><p>解除 alternation 后:c11 → c12 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c10 → c14 → c13 → c9 → c6 → c5</p></details></article><article><h2>146 · 留住通路 · 奇偶 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 143.56220453588912 450" role="img" aria-label="奇偶 · 墙的选择"><polygon points="79.17840259193665,45.625 64.38380194395248,71.25 34.79460064798417,71.25 20,45.625 34.79460064798415,20.000000000000004 64.38380194395248,20" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="123.56220453588912,71.25 108.76760388790495,96.875 79.17840259193665,96.875 64.38380194395248,71.25 79.17840259193662,45.625 108.76760388790495,45.625" fill="#f1eef9" stroke="#aaa1c7" 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c13</p></details></div><h3>推理依据</h3><ul><li>c4 为第6步,要求偶</li><li>墙 c8—c9 封闭该邻接</li></ul><p>关键分叉:第 5 步应走 c5,诱惑路线走 c4。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c4 后:c0 → c2 → c1 → c3 → c4 → c5 → c6 → c7 → c8 → c10 → c9 → c11 → c12 → c14 → c13</p><p>解除 wall:0 后:c0 → c2 → c1 → c3 → c5 → c4 → c6 → c7 → c8 → c9 → c10 → c11 → c12 → c14 → c13</p></details></article><article><h2>147 · 留住通路 · 通道 · 奇偶的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="通道 · 奇偶的选择"><polygon points="184,20 348,20 348,102 266,102 266,184 184,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 102,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,20 102,20 102,102 20,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,102 184,102 184,184 102,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,102 102,102 102,184 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text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c14</text></svg></figure><p>c14 → c13 → c12 → c8 → c9 → c5 → c6 → c10 → c11 → c7 → c4 → c2 → c1 → c0 → c3</p></details></div><h3>推理依据</h3><ul><li>c1 为第13步,要求奇</li><li>c1 必须左右直行</li><li>c6 必须右与下拐角</li></ul><p>关键分叉:第 12 步应走 c2,诱惑路线走 c3。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c1 后:c14 → c13 → c12 → c8 → c9 → c5 → c6 → c10 → c11 → c7 → c4 → c3 → c0 → c1 → c2</p><p>解除 direction:c1 后:c14 → c13 → c12 → c8 → c9 → c5 → c6 → c10 → c11 → c7 → c4 → c2 → c1 → c3 → c0</p><p>解除 direction:c6 后:c14 → c13 → c12 → c8 → c9 → c10 → c11 → c7 → c4 → c2 → c1 → c0 → c3 → c6 → c5</p></details></article><article><h2>148 · 留住通路 · 通道 · 墙 · 门的交错</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="通道 · 墙 · 门的交错"><polygon points="184,20 266,20 266,102 184,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 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c5</p></details></div><h3>推理依据</h3><ul><li>c11 必须左与上拐角</li><li>墙 c8—c12 封闭该邻接</li><li>墙 c5—c6 封闭该邻接</li><li>门 c15—c12 通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 2 步应走 c4,诱惑路线走 c7。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c11 后:c3 → c7 → c8 → c9 → c5 → c4 → c0 → c1 → c2 → c6 → c10 → c14 → c13 → c16 → c15 → c12 → c11</p><p>解除 wall:0 后:c3 → c7 → c11 → c12 → c8 → c9 → c5 → c4 → c0 → c1 → c2 → c6 → c10 → c14 → c13 → c16 → c15</p><p>解除 wall:1 后:c3 → c4 → c0 → c1 → c2 → c6 → c5 → c9 → c10 → c14 → c13 → c16 → c15 → c12 → c11 → c7 → c8</p><p>解除 door:0 后:c3 → c7 → c11 → c12 → c15 → c16 → c13 → c14 → c10 → c6 → c2 → c1 → c0 → c4 → c5 → c9 → c8</p></details></article><article><h2>149 · 留住通路 · 通道 · 双色 · 墙 · 门的小径</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 双色 · 墙 · 门的小径"><polygon points="275,20 360,20 360,105 275,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon 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font-size="10" fill="#665c78">c10 · ┘ △</text><text x="232.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="232.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11 · ○</text><text x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">14</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12 · △</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">13</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13 · ○</text></svg></figure><p>c5 → c8 → c11 → c10 → c7 → c4 → c0 → c1 → c2 → c3 → c6 → c9 → c13 → c12</p></details></div><h3>推理依据</h3><ul><li>c10 必须左与上拐角</li><li>每步蓝橙交替</li><li>墙 c4—c5 封闭该邻接</li><li>门 c2—c3 通过前按已走格数切换,通过后保持开启;正确解从第9步末端通过</li></ul><p>关键分叉:第 3 步应走 c11,诱惑路线走 c7。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c10 后:c5 → c8 → c7 → c4 → c0 → c1 → c2 → c3 → c6 → c9 → c13 → c12 → c11 → c10</p><p>解除 alternation 后:c5 → c6 → c3 → c2 → c1 → c0 → c4 → c7 → c10 → c11 → c8 → c9 → c12 → c13</p><p>解除 wall:0 后:c5 → c4 → c0 → c1 → c2 → c3 → c6 → c9 → c13 → c12 → c11 → c10 → c7 → c8</p><p>解除 door:0 后:c5 → c8 → c7 → c10 → c11 → c12 → c13 → c9 → c6 → c3 → c2 → c1 → c0 → c4</p></details></article><article><h2>150 · 留住通路 · 通道 · 奇偶 · 墙 · 门的花园</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 312" role="img" aria-label="通道 · 奇偶 · 墙 · 门的花园"><polygon points="20,88 88,88 88,224 20,224" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,20 88,20 88,88 20,88" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="88,224 156,224 156,292 88,292" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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→ c5 → c3 → c1 → c0 → c2</p><p>解除 door:0 后:c8 → c10 → c11 → c9 → c7 → c6 → c4 → c2 → c0 → c1 → c3 → c5</p></details></article><article><h2>152 · 复合推理 · 双色 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="双色 · 墙的选择"><polygon points="20,20 105,20 105,190 20,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 360,105 360,190 190,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon 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→ c9 → c10 → c11</p><p>解除 wall:0 后:c4 → c2 → c0 → c1 → c3 → c5 → c6 → c7 → c8 → c9 → c10 → c11</p><p>解除 door:0 后:c4 → c2 → c0 → c1 → c3 → c5 → c6 → c7 → c9 → c11 → c10 → c8</p></details></article><article><h2>154 · 复合推理 · 奇偶 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="奇偶 · 墙的选择"><polygon points="20,20 190,20 190,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 360,105 360,190 190,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" 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text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c0</text><text x="232.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="232.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c1</text><text x="317.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">奇</text><text x="317.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="62.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="62.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="147.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="147.5" y="157.5" text-anchor="middle" font-family="system-ui" 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fill="#665c78">c8 · ○</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">7</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9 · ○</text><text x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">10</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10 · △</text><text x="232.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">9</text><text x="232.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11 · ○</text></svg></figure><p>c4 → c0 → c1 → c2 → c3 → c7 → c9 → c6 → c11 → c10 → c8 → c5</p></details></div><h3>推理依据</h3><ul><li>c0 必须右与下拐角</li><li>c1 必须左右直行</li><li>每步蓝橙交替</li></ul><p>关键分叉:第 2 步应走 c0,诱惑路线走 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c2</p></details></div><h3>推理依据</h3><ul><li>c7 为第6步,要求偶</li><li>墙 c1—c2 封闭该邻接</li></ul><p>关键分叉:第 5 步应走 c6,诱惑路线走 c7。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c7 后:c11 → c10 → c9 → c8 → c7 → c6 → c5 → c4 → c3 → c1 → c0 → c2</p><p>解除 wall:0 后:c11 → c10 → c9 → c8 → c6 → c7 → c5 → c4 → c3 → c1 → c2 → c0</p></details></article><article><h2>158 · 复合推理 · 通道 · 奇偶的交错</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 奇偶的交错"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" 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font-size="21" font-weight="700">7</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12</text><text x="232.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="232.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13</text></svg></figure><p>c9 → c6 → c5 → c4 → c8 → c11 → c12 → c13 → c10 → c7 → c3 → c2 → c1 → c0</p></details></div><h3>推理依据</h3><ul><li>c10 为第9步,要求奇</li><li>c11 必须上与右拐角</li></ul><p>关键分叉:第 2 步应走 c6,诱惑路线走 c10。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c10 后:c9 → c10 → c13 → c12 → c11 → c8 → c4 → c5 → c6 → c7 → c3 → c2 → c1 → c0</p><p>解除 direction:c11 后:c9 → c6 → c5 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c10 → c13 → c12 → c11</p></details></article><article><h2>159 · 复合推理 · 通道 · 墙 · 门的小径</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" 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→ c10 → c9 → c6 → c2 → c3 → c0 → c1</p><p>解除 alternation 后:c13 → c14 → c15 → c12 → c8 → c5 → c4 → c1 → c0 → c2 → c3 → c6 → c7 → c11 → c10 → c9</p><p>解除 wall:0 后:c13 → c14 → c15 → c12 → c11 → c10 → c9 → c6 → c2 → c3 → c0 → c1 → c4 → c5 → c8 → c7</p><p>解除 wall:1 后:c13 → c10 → c9 → c6 → c2 → c3 → c0 → c1 → c4 → c5 → c8 → c7 → c11 → c14 → c15 → c12</p><p>解除 door:0 后:c13 → c14 → c15 → c12 → c8 → c5 → c4 → c1 → c0 → c3 → c2 → c6 → c9 → c10 → c11 → c7</p></details></article><article><h2>161 · 寻找突破口 · 通道 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 墙的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" 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c8 → c12</p><p>解除 wall:0 后:c4 → c8 → c12 → c9 → c5 → c6 → c10 → c11 → c7 → c3 → c2 → c1 → c0</p></details></article><article><h2>164 · 寻找突破口 · 奇偶 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 276.7136103677466 450" role="img" aria-label="奇偶 · 墙 · 门的选择"><polygon points="256.7136103677466,389 233.04224933097194,430 185.6995272574226,430 162.02816622064796,389 185.6995272574226,348 233.04224933097194,348" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="185.6995272574226,348 162.02816622064796,389 114.68544414709864,389 91.01408311032398,348 114.68544414709862,307 162.02816622064796,307" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="114.68544414709864,307 91.01408311032398,348 43.671361036774655,348 20,307 43.67136103677464,266 91.01408311032398,266" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="256.7136103677466,307 233.04224933097194,348 185.6995272574226,348 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通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 3 步应走 c4,诱惑路线走 c1。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c1 后:c5 → c2 → c1 → c0 → c3 → c4 → c6 → c9 → c12 → c10 → c11 → c8 → c7</p><p>解除 parity:c12 后:c5 → c2 → c4 → c1 → c0 → c3 → c6 → c7 → c8 → c11 → c10 → c12 → c9</p><p>解除 wall:0 后:c5 → c4 → c2 → c1 → c0 → c3 → c6 → c9 → c12 → c10 → c11 → c8 → c7</p><p>解除 wall:1 后:c5 → c2 → c4 → c1 → c0 → c3 → c6 → c7 → c8 → c11 → c10 → c9 → c12</p><p>解除 door:0 后:c5 → c2 → c4 → c1 → c0 → c3 → c6 → c9 → c12 → c10 → c7 → c8 → c11</p></details></article><article><h2>165 · 寻找突破口 · 奇偶 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="奇偶 · 墙的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" 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font-weight="700">11</text><text x="53.81623005253522" y="352.14285714285705" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10 · ○</text><text x="104.54057513133804" y="363.4285714285714" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">13</text><text x="104.54057513133804" y="381.4285714285714" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11 · ○</text><text x="53.81623005253522" y="392.71428571428567" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">12</text><text x="53.81623005253522" y="410.71428571428567" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12 · △</text></svg></figure><p>c0 → c1 → c2 → c3 → c4 → c6 → c5 → c7 → c8 → c9 → c10 → c12 → c11</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c9—c11 封闭该邻接</li></ul><p>关键分叉:第 6 步应走 c6,诱惑路线走 c5。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c0 → c1 → c2 → c3 → c4 → c5 → c6 → c7 → c8 → c9 → c10 → c11 → c12</p><p>解除 wall:0 后:c0 → c1 → c2 → c3 → c4 → c6 → c5 → c7 → c8 → c9 → c11 → c12 → c10</p></details></article><article><h2>167 · 寻找突破口 · 通道 · 双色的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 双色的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#ffae55" stroke="#aaa1c7" 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c3 → c2 → c1 → c0 → c4 → c8 → c12</p><p>解除 alternation 后:c11 → c7 → c3 → c2 → c6 → c10 → c9 → c12 → c8 → c4 → c0 → c1 → c5</p></details></article><article><h2>168 · 寻找突破口 · 奇偶 · 墙的交错</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 143.56220453588912 450" role="img" aria-label="奇偶 · 墙的交错"><polygon points="79.17840259193665,45.625 64.38380194395248,71.25 34.79460064798417,71.25 20,45.625 34.79460064798415,20.000000000000004 64.38380194395248,20" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="123.56220453588912,71.25 108.76760388790495,96.875 79.17840259193665,96.875 64.38380194395248,71.25 79.17840259193662,45.625 108.76760388790495,45.625" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="79.17840259193665,96.875 64.38380194395248,122.49999999999999 34.79460064798417,122.49999999999999 20,96.875 34.79460064798415,71.25 64.38380194395248,71.25" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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c9 → c8 → c10 → c11 → c13 → c12 → c14</p><p>解除 wall:1 后:c1 → c0 → c2 → c3 → c4 → c5 → c6 → c7 → c8 → c9 → c10 → c11 → c13 → c14 → c12</p></details></article><article><h2>169 · 寻找突破口 · 通道 · 奇偶的小径</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="通道 · 奇偶的小径"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 327.5,122.5 225,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 122.5,122.5 122.5,225 20,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,122.5 225,122.5 225,225 122.5,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,122.5 327.5,122.5 327.5,225 225,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,225 122.5,225 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font-size="21" font-weight="700">13</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12</text></svg></figure><p>c11 → c10 → c9 → c5 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c12</p></details></div><h3>推理依据</h3><ul><li>c7 必须左与上拐角</li><li>墙 c8—c9 封闭该邻接</li><li>门 c1—c0 通过前按已走格数切换,通过后保持开启;正确解从第9步末端通过</li></ul><p>关键分叉:第 1 步应走 c11,诱惑路线走 c3。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c7 后:c3 → c2 → c6 → c7 → c11 → c10 → c9 → c5 → c1 → c0 → c4 → c8 → c12</p><p>解除 wall:0 后:c11 → c10 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c9 → c8 → c12</p><p>解除 door:0 后:c12 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c6 → c5 → c9 → c10 → c11</p></details></article><article><h2>171 · 长线布局 · 双色 · 奇偶 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="双色 · 奇偶 · 墙的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 275,20 275,105 190,105 190,190 105,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,190 190,190 190,275 105,275" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,190 275,190 275,275 190,275" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,190 360,190 360,275 275,275" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,275 105,275 105,360 20,360" fill="#64acf3" 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YaHei" font-size="21" font-weight="700">奇 ○</text><text x="317.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="62.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="62.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="232.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="232.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="317.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="317.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="62.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="62.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="147.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="147.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text><text x="232.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="232.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10</text><text x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="双色 · 奇偶 · 墙的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 275,20 275,105 190,105 190,190 105,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#64acf3" 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font-family="system-ui" font-size="10" fill="#665c78">c1</text><text x="225" y="53" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="225" y="71" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="307" y="53" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="307" y="71" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="61" y="135" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="61" y="153" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="143" y="135" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="143" y="153" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text 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格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="双色 · 墙的选择"><polygon points="20,20 102,20 102,102 20,102" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 102,102" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,20 266,20 266,102 184,102" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,20 348,20 348,102 266,102" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,102 102,102 102,184 20,184" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,102 184,102 184,184 102,184" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,102 348,102 348,184 266,184 266,266 184,266" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,184 102,184 102,266 20,266" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,184 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c0</p></details></div><h3>推理依据</h3><ul><li>c6 为第7步,要求奇</li><li>墙 c0—c1 封闭该邻接</li></ul><p>关键分叉:第 6 步应走 c5,诱惑路线走 c6。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c6 后:c11 → c10 → c9 → c8 → c7 → c6 → c5 → c4 → c3 → c1 → c2 → c0</p><p>解除 wall:0 后:c11 → c10 → c9 → c8 → c7 → c5 → c6 → c4 → c3 → c1 → c0 → c2</p></details></article><article><h2>180 · 长线布局 · 通道 · 奇偶的花园</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="通道 · 奇偶的花园"><polygon points="20,20 184,20 184,102 102,102 102,184 20,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,20 266,20 266,102 184,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,20 348,20 348,102 266,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,102 184,102 184,184 102,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,102 266,102 266,184 184,184" fill="#f1eef9" 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→ c0 → c6 → c7 → c3 → c4 → c8 → c11 → c13 → c10</p></details></article><article><h2>181 · 综合挑战 · 通道 · 奇偶 · 墙 · 门的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="通道 · 奇偶 · 墙 · 门的选择"><polygon points="20,20 102,20 102,102 20,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 102,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,20 266,20 266,102 184,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,20 348,20 348,102 266,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,102 102,102 102,184 20,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,102 184,102 184,184 102,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,102 348,102 348,184 184,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,184 102,184 102,266 20,266" 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font-family="system-ui" font-size="10" fill="#665c78">c9</text><text x="307" y="217" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="307" y="235" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10</text><text x="61" y="299" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">2</text><text x="61" y="317" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text><text x="143" y="299" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">5</text><text x="143" y="317" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12</text><text x="307" y="299" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">7</text><text x="307" y="317" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13</text><text x="61" y="381" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="61" y="399" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c14</text></svg></figure><p>c14 → c11 → c7 → c8 → c12 → c9 → c13 → c10 → c6 → c2 → c1 → c5 → c4 → c0 → c3</p></details></div><h3>推理依据</h3><ul><li>c4 为第13步,要求奇</li><li>墙 c3—c4 封闭该邻接</li><li>门 c1—c5 通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 3 步应走 c7,诱惑路线走 c12。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c4 后:c14 → c11 → c12 → c9 → c5 → c4 → c8 → c7 → c3 → c0 → c1 → c2 → c6 → c10 → c13</p><p>解除 wall:0 后:c14 → c11 → c7 → c8 → c12 → c9 → c13 → c10 → c6 → c2 → c1 → c5 → c4 → c3 → c0</p><p>解除 door:0 后:c14 → c11 → c12 → c9 → c8 → c7 → c3 → c0 → c4 → c5 → c1 → c2 → c6 → c10 → c13</p></details></article><article><h2>183 · 综合挑战 · 通道 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="通道 · 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c4 → c5 → c7 → c9 → c11 → c13 → c14 → c12 → c10 → c8 → c6</p><p>解除 wall:1 后:c0 → c1 → c2 → c3 → c4 → c5 → c6 → c8 → c7 → c9 → c10 → c12 → c11 → c13 → c14</p><p>解除 door:0 后:c0 → c1 → c2 → c3 → c4 → c5 → c6 → c8 → c10 → c12 → c14 → c13 → c11 → c9 → c7</p></details></article><article><h2>185 · 综合挑战 · 双色 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="双色 · 墙的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#ffae55" 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font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">7</text><text x="49.58920129596832" y="209.375" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="93.9730032399208" y="216.99999999999997" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">9</text><text x="93.9730032399208" y="234.99999999999997" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text><text x="49.58920129596832" y="242.62499999999997" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">8</text><text x="49.58920129596832" y="260.625" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text><text x="93.9730032399208" y="268.24999999999994" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">10</text><text x="93.9730032399208" y="286.24999999999994" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text><text x="49.58920129596832" y="293.875" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">11</text><text x="49.58920129596832" y="311.875" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10</text><text x="93.9730032399208" y="319.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">12</text><text x="93.9730032399208" y="337.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text><text x="49.58920129596832" y="345.125" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">14</text><text x="49.58920129596832" y="363.125" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12</text><text x="93.9730032399208" y="370.75" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">13</text><text x="93.9730032399208" y="388.75" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13</text><text x="49.58920129596832" y="396.375" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">15</text><text x="49.58920129596832" y="414.375" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c14</text></svg></figure><p>c2 → c0 → c1 → c3 → c5 → c4 → c6 → c8 → c7 → c9 → c10 → c11 → c13 → c12 → c14</p></details></div><h3>推理依据</h3><ul><li>c5 为第5步,要求奇</li><li>墙 c9—c11 封闭该邻接</li></ul><p>关键分叉:第 5 步应走 c5,诱惑路线走 c4。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c5 后:c2 → c0 → c1 → c3 → c4 → c5 → c6 → c8 → c7 → c9 → c10 → c11 → c13 → c12 → c14</p><p>解除 wall:0 后:c2 → c0 → c1 → c3 → c5 → c4 → c6 → c8 → c7 → c9 → c11 → c13 → c14 → c12 → c10</p></details></article><article><h2>191 · 最后的花园 · 双色 · 奇偶 · 墙的选择</h2><div class="boards"><figure><svg 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fill="#665c78">c1</text><text x="232.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="232.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="317.5" y="97" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="317.5" y="115" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="62.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="62.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="147.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="147.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="232.5" y="139.5" 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y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text></svg></figure><p>c11 → c7 → c8 → c4 → c3 → c0 → c1 → c2 → c6 → c10 → c9 → c5</p></details></div><h3>推理依据</h3><ul><li>c10 为第10步,要求偶</li><li>墙 c3—c7 封闭该邻接</li><li>门 c9—c5 通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 4 步应走 c4,诱惑路线走 c9。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c10 后:c11 → c7 → c8 → c9 → c10 → c6 → c2 → c5 → c4 → c1 → c0 → c3</p><p>解除 wall:0 后:c11 → c7 → c3 → c0 → c1 → c2 → c6 → c10 → c9 → c5 → c4 → c8</p><p>解除 door:0 后:c11 → c7 → c8 → c9 → c5 → c4 → c3 → c0 → c1 → c2 → c6 → c10</p></details></article><article><h2>194 · 最后的花园 · 通道 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="通道 · 墙的选择"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" 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c5 → c3 → c1 → c0 → c2 → c4</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c2—c3 封闭该邻接</li><li>门 c1—c0 通过前按已走格数切换,通过后保持开启;正确解从第9步末端通过</li></ul><p>关键分叉:第 8 步应走 c3,诱惑路线走 c4。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c8 → c10 → c11 → c9 → c7 → c6 → c5 → c4 → c3 → c1 → c2 → c0</p><p>解除 wall:0 后:c8 → c10 → c11 → c9 → c7 → c6 → c5 → c4 → c2 → c3 → c1 → c0</p><p>解除 door:0 后:c8 → c10 → c11 → c9 → c7 → c6 → c5 → c4 → c2 → c0 → c1 → c3</p></details></article><article><h2>196 · 最后的花园 · 双色 · 墙的选择</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="双色 · 墙的选择"><polygon points="20,20 105,20 105,105 20,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" 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c11</p></details></div><h3>推理依据</h3><ul><li>c6 为第7步,要求奇</li><li>墙 c1—c3 封闭该邻接</li><li>门 c9—c11 通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 7 步应走 c6,诱惑路线走 c7。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c6 后:c0 → c1 → c2 → c3 → c4 → c5 → c7 → c6 → c8 → c10 → c9 → c11</p><p>解除 wall:0 后:c0 → c1 → c3 → c2 → c4 → c5 → c6 → c7 → c8 → c10 → c9 → c11</p><p>解除 door:0 后:c0 → c1 → c2 → c3 → c4 → c5 → c6 → c8 → c10 → c11 → c9 → c7</p></details></article><article><h2>198 · 最后的花园 · 奇偶 · 墙的交错</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="奇偶 · 墙的交错"><polygon points="20,20 102,20 102,184 20,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 102,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,20 266,20 266,102 184,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,20 348,20 348,102 266,102" fill="#f1eef9" 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font-weight="700">6</text><text x="275" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5 · △</text><text x="62.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">12</text><text x="62.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6 · △</text><text x="147.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">9</text><text x="147.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7 · ┌ ○</text><text x="232.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="232.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8 · △</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">7</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9 · ○</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">11</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10 · ○</text><text x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">10</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11 · △</text></svg></figure><p>c3 → c2 → c1 → c0 → c4 → c5 → c9 → c8 → c7 → c11 → c10 → c6</p></details></div><h3>推理依据</h3><ul><li>c7 必须右与下拐角</li><li>每步蓝橙交替</li></ul><p>关键分叉:第 10 步应走 c11,诱惑路线走 c6。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c7 后:c3 → c2 → c1 → c0 → c4 → c5 → c9 → c8 → c7 → c6 → c10 → c11</p><p>解除 alternation 后:c3 → c2 → c1 → c0 → c6 → c10 → c11 → c7 → c8 → c9 → c5 → c4</p></details></article></html>