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<!doctype html><html lang="zh-CN"><meta charset="utf-8"><meta name="viewport" content="width=device-width,initial-scale=1"><title>步进开关门 · 设计评审</title><style>body{max-width:920px;margin:24px auto;padding:0 18px;background:#f7f5fb;color:#303047;font:15px/1.7 system-ui,'Microsoft YaHei'}article{background:white;border:1px solid #ddd5ed;border-radius:16px;padding:20px;margin:20px 0;break-inside:avoid}.boards{display:flex;gap:24px;flex-wrap:wrap}figure{margin:0;width:380px;max-width:100%}svg{max-height:450px;width:100%}details{cursor:pointer}a{color:#6552aa}@media print{body{background:white}article{border:none;page-break-after:always}} </style><a href="play.html">进入试玩</a><h1>步进开关门 · 8关设计评审</h1><p>只有一道门,没有开关格。空盘门关;每落一格就切换一次,包括起点:第1格后开、第2格后关。移动前看当前门位,落格后再切换。不能原地等待切换,撤销会倒回状态。</p><p>原始盘面和作者解分开展示。标题是设计任务,真人推理路径与难度仍需试玩验证。数字、窗口、方向、类别和开关显示在格内;步差与先后关系见逐关推理依据。</p><article><h2>01 · 入门 · 第一步后门开:认识落格切换</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 266.66666666666663" role="img" aria-label="第一步后门开:认识落格切换"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 133.33333333333331,133.33333333333331 133.33333333333331,246.66666666666666 20,246.66666666666666" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,133.33333333333331 246.66666666666666,133.33333333333331 246.66666666666666,246.66666666666666 133.33333333333331,246.66666666666666" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,133.33333333333331 360,133.33333333333331 360,246.66666666666666 246.66666666666666,246.66666666666666" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><line x1="303.3333333333333" y1="90.26666666666665" x2="303.3333333333333" y2="176.39999999999998" stroke="#aa4d25" stroke-width="8" transform="rotate(-90 303.3333333333333 133.33333333333331)"/><text x="311.3333333333333" y="125.33333333333331" font-size="12">步进门</text><text x="76.66666666666666" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="76.66666666666666" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c0</text><text x="190" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="190" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c1</text><text x="303.3333333333333" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">4</text><text x="303.3333333333333" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="76.66666666666666" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="76.66666666666666" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="190" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="190" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="303.3333333333333" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 266.66666666666663" role="img" aria-label="第一步后门开:认识落格切换"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 133.33333333333331,133.33333333333331 133.33333333333331,246.66666666666666 20,246.66666666666666" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,133.33333333333331 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font-weight="700">6</text><text x="76.66666666666666" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c0</text><text x="190" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">5</text><text x="190" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c1</text><text x="303.3333333333333" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">4</text><text x="303.3333333333333" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="76.66666666666666" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="76.66666666666666" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="190" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">2</text><text x="190" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="303.3333333333333" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text></svg></figure><p>c3 → c4 → c5 → c2 → c1 → c0</p></details></div><h3>推理依据</h3><ul><li>第 3 格后门开,从 c5 走向 c2,落格后门关;空盘门关、起步也切换</li></ul><p>关键分叉:第 2 步应走 c4,诱惑路线走 c0。排除依据:这一步门是关闭的。</p><details><summary>逐项机制必要性反例</summary><p>解除 door:0 后:c3 → c0 → c1 → c2 → c5 → c4</p></details></article><article><h2>02 · 入门 · 第二步后门关:先绕行再通过</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="第二步后门关:先绕行再通过"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 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stroke-width="2"/><polygon points="20,246.66666666666666 133.33333333333331,246.66666666666666 133.33333333333331,360 20,360" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,246.66666666666666 246.66666666666666,246.66666666666666 246.66666666666666,360 133.33333333333331,360" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><line x1="133.33333333333331" y1="33.599999999999994" x2="133.33333333333331" y2="119.73333333333332" stroke="#aa4d25" stroke-width="8" transform="rotate(0 133.33333333333331 76.66666666666666)"/><text x="141.33333333333331" y="68.66666666666666" font-size="12">步进门</text><text x="76.66666666666666" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="76.66666666666666" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c0</text><text x="190" y="68.66666666666666" text-anchor="middle" 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y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="76.66666666666666" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="76.66666666666666" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="190" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="190" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="第二步后门关:先绕行再通过"><polygon points="20,20 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text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="190" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="190" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="303.3333333333333" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="76.66666666666666" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="76.66666666666666" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="190" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">2</text><text x="190" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text></svg></figure><p>c4 → c7 → c6 → c3 → c0 → c1 → c2 → c5</p></details></div><h3>推理依据</h3><ul><li>第 5 格后门开,从 c0 走向 c1,落格后门关;空盘门关、起步也切换</li></ul><p>关键分叉:第 2 步应走 c7,诱惑路线走 c5。排除依据:这一步门是关闭的。</p><details><summary>逐项机制必要性反例</summary><p>解除 door:0 后:c4 → c5 → c2 → c1 → c0 → c3 → c6 → c7</p></details></article><article><h2>03 · 普通 · 门旁近路被当前状态挡住</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 295" role="img" aria-label="门旁近路被当前状态挡住"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" 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font-size="21" font-weight="700">8</text><text x="232.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text></svg></figure><p>c3 → c2 → c1 → c0 → c4 → c5 → c8 → c9 → c6 → c7</p></details></div><h3>推理依据</h3><ul><li>第 3 格后门开,从 c1 走向 c0,落格后门关;空盘门关、起步也切换</li></ul><p>关键分叉:第 2 步应走 c2,诱惑路线走 c7。排除依据:这一步门是关闭的。</p><details><summary>逐项机制必要性反例</summary><p>解除 door:0 后:c3 → c7 → c6 → c9 → c8 → c5 → c4 → c0 → c1 → c2</p></details></article><article><h2>04 · 普通 · 用中段数字推算门的开关</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 295" role="img" aria-label="用中段数字推算门的开关"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" 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YaHei" font-size="21" font-weight="700">4</text><text x="62.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text><text x="147.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="147.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text><text x="232.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="232.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg 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fill="#665c78">c13</text><text x="232.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">11</text><text x="232.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c14</text><text x="317.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">12</text><text x="317.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c15</text></svg></figure><p>c3 → c2 → c1 → c0 → c4 → c8 → c12 → c13 → c9 → c10 → c14 → c15 → c11 → c7 → c6 → c5</p></details></div><h3>推理依据</h3><ul><li>第 13 格后门开,从 c11 走向 c7,落格后门关;空盘门关、起步也切换</li></ul><p>关键分叉:第 9 步应走 c9,诱惑路线走 c14。排除依据:这一步门是关闭的。</p><details><summary>逐项机制必要性反例</summary><p>解除 door:0 后:c3 → c2 → c1 → c0 → c4 → c8 → c12 → c13 → c14 → c10 → c9 → c5 → c6 → c7 → c11 → c15</p></details></article><article><h2>07 · 难 · 长区间内安排一次正确穿门</h2><div class="boards"><figure><svg 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c9。排除依据:这一步门是关闭的。</p><details><summary>逐项机制必要性反例</summary><p>解除 door:0 后:c0 → c1 → c5 → c4 → c8 → c12 → c13 → c9 → c10 → c6 → c2 → c3 → c7 → c11 → c15 → c14 → c17 → c16</p></details></article><article><h2>08 · 难 · 起点未知:同时推起点与穿门时机</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="起点未知:同时推起点与穿门时机"><polygon points="20,20 102,20 102,102 20,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 102,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,20 266,20 266,102 184,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,20 348,20 348,102 266,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,102 102,102 102,184 20,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,102 184,102 184,184 102,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,102 266,102 266,184 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→ c10 → c14 → c15 → c11 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c9 → c13 → c12 → c16 → c17 → c18</p></details></article></html>