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<!doctype html><html lang="zh-CN"><meta charset="utf-8"><meta name="viewport" content="width=device-width,initial-scale=1"><title>路径开门 · 设计评审</title><style>body{max-width:920px;margin:24px auto;padding:0 18px;background:#f7f5fb;color:#303047;font:15px/1.7 system-ui,'Microsoft YaHei'}article{background:white;border:1px solid #ddd5ed;border-radius:16px;padding:20px;margin:20px 0;break-inside:avoid}.boards{display:flex;gap:24px;flex-wrap:wrap}figure{margin:0;width:380px;max-width:100%}svg{max-height:450px;width:100%}details{cursor:pointer}a{color:#6552aa}@media print{body{background:white}article{border:none;page-break-after:always}} </style><a href="play.html">进入试玩</a><h1>路径开门 · 8关设计评审</h1><p>每格一次。门初始关闭,走到编号对应的开关后永久打开;撤销会恢复门的状态。</p><p>原始盘面和作者解分开展示。标题是设计任务,真人推理路径与难度仍需试玩验证。数字、窗口、方向、类别和开关显示在格内;步差与先后关系见逐关推理依据。</p><article><h2>01 · 入门 · 先踩开关再过门</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 266.66666666666663" role="img" aria-label="先踩开关再过门"><polygon 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font-weight="700"></text><text x="303.3333333333333" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="76.66666666666666" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="76.66666666666666" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="190" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="190" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="303.3333333333333" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 266.66666666666663" role="img" aria-label="先踩开关再过门"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 133.33333333333331,133.33333333333331 133.33333333333331,246.66666666666666 20,246.66666666666666" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,133.33333333333331 246.66666666666666,133.33333333333331 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font-family="system-ui" font-size="10" fill="#665c78">c0 · 开1</text><text x="190" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="190" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c1</text><text x="303.3333333333333" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">6</text><text x="303.3333333333333" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="76.66666666666666" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="76.66666666666666" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="190" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">4</text><text x="190" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="303.3333333333333" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">5</text><text x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text></svg></figure><p>c1 → c0 → c3 → c4 → c5 → c2</p></details></div><h3>推理依据</h3><ul><li>先在第 2 步踩 c0,第 5 步跨门 c4—c5</li></ul><p>关键分叉:第 2 步应走 c0,诱惑路线走 c2。排除依据:开关尚未打开此门。</p><details><summary>逐项机制必要性反例</summary><p>解除 gate:0 后:c1 → c2 → c5 → c4 → c3 → c0</p></details></article><article><h2>02 · 入门 · 绕行到开关</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="绕行到开关"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 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x="190" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="303.3333333333333" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="76.66666666666666" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">5</text><text x="76.66666666666666" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="190" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">6</text><text x="190" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text></svg></figure><p>c2 → c1 → c0 → c3 → c6 → c7 → c4 → c5</p></details></div><h3>推理依据</h3><ul><li>先在第 3 步踩 c0,第 7 步跨门 c7—c4</li></ul><p>关键分叉:第 2 步应走 c1,诱惑路线走 c5。排除依据:开关尚未打开此门。</p><details><summary>逐项机制必要性反例</summary><p>解除 gate:0 后:c2 → c5 → c4 → c7 → c6 → c3 → c0 → c1</p></details></article><article><h2>03 · 普通 · 开门后不能立刻穿过去</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 295" role="img" aria-label="开门后不能立刻穿过去"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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c4</p></details></div><h3>推理依据</h3><ul><li>先在第 4 步踩 c3,第 7 步跨门 c6—c9</li></ul><p>关键分叉:第 2 步应走 c1,诱惑路线走 c4。排除依据:开关尚未打开此门。</p><details><summary>逐项机制必要性反例</summary><p>解除 gate:0 后:c0 → c4 → c5 → c8 → c9 → c6 → c7 → c3 → c2 → c1</p></details></article><article><h2>04 · 普通 · 两对独立门与开关</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 295" role="img" aria-label="两对独立门与开关"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" 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c9,第 6 步跨门 c4—c0</li><li>先在第 6 步踩 c0,第 11 步跨门 c7—c11</li></ul><p>关键分叉:第 3 步应走 c9,诱惑路线走 c1。排除依据:开关尚未打开此门。</p><details><summary>逐项机制必要性反例</summary><p>解除 gate:0 后:c6 → c5 → c1 → c0 → c4 → c8 → c9 → c12 → c13 → c10 → c11 → c7 → c3 → c2</p><p>解除 gate:1 后:c6 → c2 → c3 → c7 → c11 → c10 → c13 → c12 → c9 → c8 → c4 → c0 → c1 → c5</p></details></article><article><h2>06 · 进阶 · 开关顺序与区域收尾</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="开关顺序与区域收尾"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" 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c10 → c9</p></details></article><article><h2>07 · 难 · 三对门形成依赖链</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="三对门形成依赖链"><polygon points="20,20 102,20 102,102 20,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 102,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,20 266,20 266,102 184,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,20 348,20 348,102 266,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,102 102,102 102,184 20,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,102 184,102 184,184 102,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,102 266,102 266,184 184,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,102 348,102 348,184 266,184" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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font-weight="700">8</text><text x="143" y="399" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c17</text><text x="225" y="381" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">7</text><text x="225" y="399" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c18 · 开2</text></svg></figure><p>c2 → c3 → c7 → c11 → c15 → c14 → c18 → c17 → c16 → c12 → c13 → c9 → c8 → c4 → c0 → c1 → c5 → c6 → c10</p></details></div><h3>推理依据</h3><ul><li>先在第 3 步踩 c7,第 6 步跨门 c15—c14</li><li>先在第 7 步踩 c18,第 11 步跨门 c12—c13</li><li>先在第 6 步踩 c14,第 16 步跨门 c0—c1</li></ul><p>关键分叉:第 1 步应走 c2,诱惑路线走 c5。排除依据:开关尚未打开此门。</p><details><summary>逐项机制必要性反例</summary><p>解除 gate:0 后:c5 → c6 → c10 → c11 → c15 → c14 → c18 → c17 → c16 → c12 → c13 → c9 → c8 → c4 → c0 → c1 → c2 → c3 → c7</p><p>解除 gate:1 后:c2 → c3 → c7 → c11 → c15 → c14 → c10 → c6 → c5 → c1 → c0 → c4 → c8 → c9 → c13 → c12 → c16 → c17 → c18</p><p>解除 gate:2 后:c13 → c9 → c10 → c11 → c7 → c3 → c2 → c6 → c5 → c1 → c0 → c4 → c8 → c12 → c16 → c17 → c18 → c14 → c15</p></details></article></html>