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<!doctype html><html lang="zh-CN"><meta charset="utf-8"><meta name="viewport" content="width=device-width,initial-scale=1"><title>53关DEMO · 设计评审</title><style>body{max-width:920px;margin:24px auto;padding:0 18px;background:#f7f5fb;color:#303047;font:15px/1.7 system-ui,'Microsoft YaHei'}article{background:white;border:1px solid #ddd5ed;border-radius:16px;padding:20px;margin:20px 0;break-inside:avoid}.boards{display:flex;gap:24px;flex-wrap:wrap}figure{margin:0;width:380px;max-width:100%}svg{max-height:450px;width:100%}details{cursor:pointer}a{color:#6552aa}@media print{body{background:white}article{border:none;page-break-after:always}} </style><a href="index.html">进入试玩</a><h1>53关DEMO · 53关设计评审</h1><p>每格一次;数字为访问步号,各关显示当前启用规则。</p><p>原始盘面和作者解分开展示。标题是设计任务,真人推理路径与难度仍需试玩验证。数字、窗口、方向、类别和开关显示在格内;步差与先后关系见逐关推理依据。</p><article><h2>1 · 覆盖、大格与墙 · 第一笔</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 266.66666666666663" role="img" aria-label="第一笔"><polygon 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font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="76.66666666666666" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c0</text><text x="190" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="190" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c1</text><text x="303.3333333333333" y="68.66666666666666" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">5</text><text x="303.3333333333333" y="86.66666666666666" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="76.66666666666666" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="76.66666666666666" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="190" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="190" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 266.66666666666663" role="img" aria-label="第一笔"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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c2</p></details></div><h3>推理依据</h3><ul></ul><p>关键分叉:第 0 步应走 c4,诱惑路线走 数字不符的候选路线。排除依据:基础数字约束。</p><details><summary>逐项机制必要性反例</summary></details></article><article><h2>2 · 覆盖、大格与墙 · 先收短支路</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="先收短支路"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 133.33333333333331,133.33333333333331 133.33333333333331,246.66666666666666 20,246.66666666666666" fill="#f1eef9" stroke="#aaa1c7" 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fill="#665c78">c7</text></svg></figure><p>c1 → c2 → c5 → c4 → c7 → c6 → c3 → c0</p></details></div><h3>推理依据</h3><ul></ul><p>关键分叉:第 0 步应走 c1,诱惑路线走 数字不符的候选路线。排除依据:基础数字约束。</p><details><summary>逐项机制必要性反例</summary></details></article><article><h2>3 · 覆盖、大格与墙 · 大块一步</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="大块一步"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 327.5,122.5 225,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 122.5,122.5 122.5,225 20,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,122.5 327.5,122.5 327.5,327.5 122.5,327.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,225 122.5,225 122.5,327.5 20,327.5" fill="#f1eef9" 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font-weight="700"></text><text x="147.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="275" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="275" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="62.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="62.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text><text x="147.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="147.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="枢纽留后"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 360,105 360,275 190,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 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数字不符的候选路线。排除依据:基础数字约束。</p><details><summary>逐项机制必要性反例</summary></details></article><article><h2>5 · 覆盖、大格与墙 · 认清异形共边</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="认清异形共边"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 360,20 360,105 275,105 275,190 190,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,190 190,190 190,275 105,275" 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font-size="10" fill="#665c78">c8</text></svg></figure><p>c6 → c7 → c8 → c5 → c4 → c3 → c0 → c1 → c2</p></details></div><h3>推理依据</h3><ul><li>墙 c3—c6 封闭该邻接</li></ul><p>关键分叉:第 2 步应走 c7,诱惑路线走 c3。排除依据:永久墙不能穿过。</p><details><summary>逐项机制必要性反例</summary><p>解除 wall:0 后:c6 → c3 → c4 → c7 → c8 → c5 → c2 → c1 → c0</p></details></article><article><h2>7 · 覆盖、大格与墙 · 近路要绕</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="近路要绕"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 327.5,122.5 225,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 122.5,122.5 122.5,225 20,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,122.5 225,122.5 225,225 122.5,225" fill="#f1eef9" stroke="#aaa1c7" 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x="303.3333333333333" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="76.66666666666666" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="76.66666666666666" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="190" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">2</text><text x="190" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text><text x="303.3333333333333" y="295.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="303.3333333333333" y="313.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text></svg></figure><p>c8 → c7 → c6 → c3 → c0 → c1 → c2 → c5 → c4</p></details></div><h3>推理依据</h3><ul><li>墙 c1—c4 封闭该邻接</li></ul><p>关键分叉:第 7 步应走 c2,诱惑路线走 c4。排除依据:永久墙不能穿过。</p><details><summary>逐项机制必要性反例</summary><p>解除 wall:0 后:c8 → c7 → c6 → c3 → c0 → c1 → c4 → c5 → c2</p></details></article><article><h2>10 · 覆盖、大格与墙 · 对称小花园</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="对称小花园"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 360,20 360,190 190,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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t3。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:t1 后:t0 → t3 → t4 → t1 → t2 → t5</p></details></article><article><h2>12 · 方向与双色 · 引导:拐角通道</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 266.66666666666663" role="img" aria-label="引导:拐角通道"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 133.33333333333331,133.33333333333331 133.33333333333331,246.66666666666666 20,246.66666666666666" fill="#f1eef9" stroke="#aaa1c7" 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fill="#665c78">t5</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 266.66666666666663" role="img" aria-label="引导:拐角通道"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 133.33333333333331,133.33333333333331 133.33333333333331,246.66666666666666 20,246.66666666666666" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,133.33333333333331 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x="71.25" y="388.75" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text></svg></figure><p>c9 → c6 → c3 → c0 → c1 → c4 → c7 → c8 → c5 → c2</p></details></div><h3>推理依据</h3><ul><li>c4 必须上下直行</li></ul><p>关键分叉:第 6 步应走 c4,诱惑路线走 c2。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c4 后:c9 → c6 → c3 → c0 → c1 → c2 → c5 → c4 → c7 → c8</p></details></article><article><h2>15 · 方向与双色 · 认清拐角</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="认清拐角"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 327.5,122.5 225,122.5" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 122.5,122.5 122.5,225 20,225" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon 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c4</p></details></div><h3>推理依据</h3><ul><li>c6 必须下与左拐角</li><li>c10 必须上与右拐角</li><li>墙 c4—c8 封闭该邻接</li></ul><p>关键分叉:第 5 步应走 c6,诱惑路线走 c4。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c6 后:c12 → c8 → c9 → c5 → c4 → c0 → c1 → c2 → c3 → c7 → c6 → c10 → c11</p><p>解除 direction:c10 后:c12 → c8 → c9 → c10 → c6 → c5 → c4 → c0 → c1 → c2 → c3 → c7 → c11</p><p>解除 wall:0 后:c12 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c11 → c10 → c6 → c5 → c9</p></details></article><article><h2>17 · 方向与双色 · 直线与拐角</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="直线与拐角"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" 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font-size="10" fill="#665c78">c9</text><text x="232.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">10</text><text x="232.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">13</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12</text><text x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">12</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13</text></svg></figure><p>c11 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c6 → c10 → c9 → c13 → c12 → c8</p></details></div><h3>推理依据</h3><ul><li>c0 必须右与下拐角</li><li>c5 必须左右直行</li><li>墙 c8—c9 封闭该邻接</li></ul><p>关键分叉:第 2 步应走 c7,诱惑路线走 c10。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c0 后:c11 → c10 → c9 → c13 → c12 → c8 → c4 → c5 → c6 → c7 → c3 → c2 → c1 → c0</p><p>解除 direction:c5 后:c11 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c12 → c13 → c9 → c5 → c6 → c10</p><p>解除 wall:0 后:c11 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c6 → c10 → c9 → c8 → c12 → c13</p></details></article><article><h2>18 · 方向与双色 · 引导:蓝橙交替</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="引导:蓝橙交替"><polygon points="20,190 190,190 190,360 20,360" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,20 360,20 360,190 20,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,190 360,190 360,360 190,360" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><text x="105" y="267" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="105" y="285" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t0 · ○</text><text x="190" y="97" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="190" y="115" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t1</text><text x="275" y="267" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="275" y="285" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">t2</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="引导:蓝橙交替"><polygon points="20,190 190,190 190,360 20,360" 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font-family="system-ui" font-size="10" fill="#665c78">t2 · ○</text></svg></figure><p>t0 → t1 → t2</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li></ul><p>关键分叉:第 2 步应走 t1,诱惑路线走 t2。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:t0 → t2 → t1</p></details></article><article><h2>19 · 方向与双色 · 蓝橙第一步</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 347.5 450" role="img" aria-label="蓝橙第一步"><polygon points="20,20 122.5,20 122.5,122.5 20,122.5" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,20 225,20 225,122.5 122.5,122.5" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="225,20 327.5,20 327.5,122.5 225,122.5" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,122.5 122.5,122.5 122.5,225 20,225" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="122.5,122.5 225,122.5 225,225 122.5,225" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon 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y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">9</text><text x="62.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7 · ○</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8 · ○</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">10</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9 · △</text><text x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">11</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10 · ○</text><text x="232.5" y="309.5" text-anchor="middle" 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text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="225" y="399" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c14 · ○</text></svg></figure><p>c14 → c13 → c12 → c8 → c9 → c6 → c5 → c0 → c3 → c10 → c11 → c7 → c4 → c2 → c1</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c9—c10 封闭该邻接</li><li>墙 c3—c6 封闭该邻接</li></ul><p>关键分叉:第 10 步应走 c10,诱惑路线走 c1。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c14 → c13 → c12 → c8 → c9 → c6 → c5 → c0 → c3 → c1 → c2 → c4 → c7 → c11 → c10</p><p>解除 wall:0 后:c14 → c13 → c12 → c8 → c5 → c6 → c9 → c10 → c3 → c0 → c1 → c2 → c4 → c7 → c11</p><p>解除 wall:1 后:c14 → c10 → c11 → c7 → c4 → c2 → c1 → c0 → c3 → c6 → c5 → c8 → c9 → c13 → c12</p></details></article><article><h2>22 · 方向与双色 · 短短的接力</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="短短的接力"><polygon points="20,20 105,20 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font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">5</text><text x="147.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c1 · ○</text><text x="232.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">7</text><text x="232.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2 · ○</text><text x="317.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="317.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3 · △</text><text x="62.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">3</text><text x="62.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4 · ○</text><text x="190" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">6</text><text x="190" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5 · △</text><text x="317.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">9</text><text x="317.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6 · ○</text><text x="62.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">2</text><text x="62.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7 · △</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">10</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8 · △</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9 · ○</text></svg></figure><p>c9 → c7 → c4 → c0 → c1 → c5 → c2 → c3 → c6 → c8</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li></ul><p>关键分叉:第 6 步应走 c5,诱惑路线走 c2。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c9 → c7 → c4 → c0 → c1 → c2 → c3 → c6 → c5 → c8</p></details></article><article><h2>23 · 方向与双色 · 双色回环</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="双色回环"><polygon points="20,20 105,20 105,105 20,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon 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text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="147.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="147.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="232.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="232.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="317.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="317.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text><text x="62.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="62.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text><text x="190" y="267" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="190" y="285" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text><text x="317.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="317.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12 · ○</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="双色回环"><polygon points="20,20 105,20 105,105 20,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon 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c11</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li></ul><p>关键分叉:第 6 步应走 c6,诱惑路线走 c1。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c12 → c10 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c6 → c9 → c8 → c11</p></details></article><article><h2>24 · 奇偶与步进门 · 偶数落脚</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="偶数落脚"><polygon points="20,20 190,20 190,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 275,105 275,190 190,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,105 360,105 360,190 275,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" fill="#f1eef9" stroke="#aaa1c7" 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y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7</text><text x="317.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">10</text><text x="317.5" y="242.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text><text x="62.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="62.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text></svg></figure><p>c9 → c5 → c0 → c6 → c7 → c3 → c1 → c2 → c4 → c8</p></details></div><h3>推理依据</h3><ul><li>c6 为第4步,要求偶</li></ul><p>关键分叉:第 3 步应走 c0,诱惑路线走 c6。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c6 后:c9 → c5 → c6 → c0 → c1 → c3 → c7 → c8 → c4 → c2</p></details></article><article><h2>25 · 奇偶与步进门 · 奇数绕行</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" 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YaHei" font-size="21" font-weight="700">1</text><text x="317.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="62.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="62.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4</text><text x="147.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="147.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text x="275" y="182" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">2</text><text x="275" y="200" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6</text><text x="62.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700"></text><text x="62.5" 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font-family="system-ui" font-size="10" fill="#665c78">c11</text></svg><figcaption>原始盘面 · 格id用于对照JSON</figcaption></figure><details><summary>展开作者解与路线</summary><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="奇数绕行"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 275,20 275,105 190,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="275,20 360,20 360,105 275,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,105 105,105 105,190 20,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,105 190,105 190,190 105,190" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,105 360,105 360,275 190,275" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,190 105,190 105,275 20,275" 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x="143" y="381" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">12</text><text x="143" y="399" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c14</text></svg></figure><p>c8 → c4 → c2 → c1 → c0 → c3 → c7 → c6 → c5 → c9 → c13 → c14 → c10 → c11 → c12</p></details></div><h3>推理依据</h3><ul><li>c6 为第8步,要求偶</li><li>c10 为第13步,要求奇</li><li>墙 c7—c8 封闭该邻接</li><li>墙 c7—c11 封闭该邻接</li></ul><p>关键分叉:第 5 步应走 c0,诱惑路线走 c3。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c6 后:c8 → c4 → c2 → c1 → c3 → c7 → c6 → c0 → c5 → c9 → c13 → c14 → c10 → c11 → c12</p><p>解除 parity:c10 后:c8 → c12 → c11 → c10 → c14 → c13 → c9 → c5 → c0 → c6 → c7 → c3 → c1 → c2 → c4</p><p>解除 wall:0 后:c8 → c7 → c3 → c4 → c2 → c1 → c0 → c6 → c5 → c9 → c13 → c14 → c10 → c11 → c12</p><p>解除 wall:1 后:c8 → c12 → c11 → c7 → c3 → c4 → c2 → c1 → c0 → c6 → c5 → c9 → c10 → c14 → c13</p></details></article><article><h2>28 · 奇偶与步进门 · 少量线索也够</h2><div 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c11</p></details></article><article><h2>29 · 奇偶与步进门 · 门随脚步开关</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="门随脚步开关"><polygon points="20,20 133.33333333333331,20 133.33333333333331,133.33333333333331 20,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,20 246.66666666666666,20 246.66666666666666,133.33333333333331 133.33333333333331,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="246.66666666666666,20 360,20 360,133.33333333333331 246.66666666666666,133.33333333333331" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,133.33333333333331 133.33333333333331,133.33333333333331 133.33333333333331,246.66666666666666 20,246.66666666666666" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="133.33333333333331,133.33333333333331 246.66666666666666,133.33333333333331 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y="381" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">11</text><text x="61" y="399" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c14</text></svg></figure><p>c9 → c8 → c5 → c6 → c2 → c3 → c7 → c10 → c13 → c12 → c14 → c11 → c4 → c0 → c1</p></details></div><h3>推理依据</h3><ul><li>门 c14—c11 通过前按已走格数切换,通过后保持开启;正确解从第11步末端通过</li></ul><p>关键分叉:第 2 步应走 c8,诱惑路线走 c10。排除依据:这一步门是关闭的。</p><details><summary>逐项机制必要性反例</summary><p>解除 door:0 后:c9 → c10 → c13 → c12 → c8 → c5 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c11 → c14</p></details></article><article><h2>32 · 奇偶与步进门 · 墙和门分开看</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 380" role="img" aria-label="墙和门分开看"><polygon points="20,20 105,20 105,105 20,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="105,20 190,20 190,105 105,105" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="190,20 360,20 360,190 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font-family="system-ui,Microsoft YaHei" font-size="12.481263092117546" font-weight="700">3</text><text x="63.038838248681195" y="365.45454545454544" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8</text><text x="127.59709562170299" y="384.7272727272727" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="12.481263092117546" font-weight="700">1</text><text x="127.59709562170299" y="402.7272727272727" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9</text></svg></figure><p>c9 → c7 → c8 → c6 → c4 → c5 → c3 → c2 → c0 → c1</p></details></div><h3>推理依据</h3><ul><li>墙 c1—c3 封闭该邻接</li></ul><p>关键分叉:第 8 步应走 c2,诱惑路线走 c1。排除依据:永久墙不能穿过。</p><details><summary>逐项机制必要性反例</summary><p>解除 wall:0 后:c9 → c7 → c8 → c6 → c4 → c5 → c3 → c1 → c0 → c2</p></details></article><article><h2>35 · 六边迁移与起点推理 · 六边留出口</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 276.7136103677466 450" role="img" 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→ c10 → c12 → c9 → c6 → c3 → c0 → c1 → c2 → c4 → c5 → c7 → c8</p><p>解除 wall:1 后:c11 → c10 → c12 → c9 → c6 → c3 → c0 → c1 → c4 → c2 → c5 → c8 → c7</p></details></article><article><h2>36 · 六边迁移与起点推理 · 六边换颜色</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 276.7136103677466 450" role="img" aria-label="六边换颜色"><polygon points="114.68544414709864,61 91.01408311032398,102 43.67136103677467,102 20,61.00000000000001 43.67136103677464,20.000000000000004 91.01408311032398,20" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="185.6995272574226,102 162.02816622064796,143 114.68544414709864,143 91.01408311032398,102 114.68544414709862,61.00000000000001 162.02816622064796,61" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="256.7136103677466,143 233.04224933097194,184 185.6995272574226,184 162.02816622064796,143 185.6995272574226,102 233.04224933097194,102" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon 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c5 → c4 → c2 → c1 → c0 → c3 → c6 → c9 → c10 → c8 → c11 → c14 → c13 → c12</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c10—c12 封闭该邻接</li><li>墙 c7—c10 封闭该邻接</li></ul><p>关键分叉:第 3 步应走 c4,诱惑路线走 c2。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c7 → c5 → c2 → c1 → c0 → c3 → c4 → c6 → c9 → c12 → c13 → c14 → c11 → c8 → c10</p><p>解除 wall:0 后:c7 → c5 → c8 → c11 → c14 → c13 → c12 → c10 → c9 → c6 → c3 → c0 → c1 → c2 → c4</p><p>解除 wall:1 后:c7 → c10 → c9 → c6 → c3 → c0 → c1 → c2 → c4 → c5 → c8 → c11 → c14 → c13 → c12</p></details></article><article><h2>38 · 六边迁移与起点推理 · 六边小花园</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 167.461174813402 450" role="img" aria-label="六边小花园"><polygon points="92.83495703622971,51.53846153846153 74.62621777717229,83.07692307692307 38.20873925905744,83.07692307692307 20,51.53846153846154 38.20873925905741,20.000000000000004 74.62621777717229,20" fill="#64acf3" stroke="#aaa1c7" 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font-weight="700">10</text><text x="56.417478518114855" y="376.9230769230769" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10 · 偶</text><text x="111.04369629528713" y="390.46153846153845" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11" font-weight="700">12</text><text x="111.04369629528713" y="408.46153846153845" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11</text></svg></figure><p>c0 → c2 → c1 → c3 → c4 → c5 → c6 → c7 → c8 → c10 → c9 → c11</p></details></div><h3>推理依据</h3><ul><li>c10 为第10步,要求偶</li><li>墙 c4—c6 封闭该邻接</li></ul><p>关键分叉:第 8 步应走 c7,诱惑路线走 c8。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c10 后:c0 → c2 → c1 → c3 → c4 → c5 → c6 → c8 → c10 → c11 → c9 → c7</p><p>解除 wall:0 后:c0 → c2 → c1 → c3 → c5 → c4 → c6 → c7 → c8 → c10 → c9 → c11</p></details></article><article><h2>43 · 六边迁移与起点推理 · 六边收束</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" 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fill="#665c78">c14</text></svg></figure><p>c11 → c7 → c6 → c10 → c14 → c13 → c12 → c8 → c9 → c5 → c4 → c0 → c1 → c2 → c3</p></details></div><h3>推理依据</h3><ul><li>c2 必须左右直行</li><li>c9 必须左与上拐角</li><li>墙 c10—c11 封闭该邻接</li></ul><p>关键分叉:第 3 步应走 c6,诱惑路线走 c3。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c2 后:c11 → c7 → c3 → c2 → c6 → c10 → c14 → c13 → c12 → c8 → c9 → c5 → c1 → c0 → c4</p><p>解除 direction:c9 后:c11 → c7 → c6 → c5 → c9 → c10 → c14 → c13 → c12 → c8 → c4 → c0 → c1 → c2 → c3</p><p>解除 wall:0 后:c11 → c10 → c14 → c13 → c12 → c8 → c9 → c5 → c6 → c7 → c3 → c2 → c1 → c0 → c4</p></details></article><article><h2>45 · 组合应用与收束 · 两个双色枢纽</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="两个双色枢纽"><polygon points="20,20 102,20 102,184 20,184" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 102,102" fill="#ffae55" stroke="#aaa1c7" stroke-width="2"/><polygon 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8 步应走 c5,诱惑路线走 c10。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c5 后:c16 → c13 → c15 → c14 → c11 → c12 → c9 → c10 → c7 → c3 → c2 → c6 → c5 → c1 → c0 → c4 → c8</p><p>解除 parity:c7 后:c16 → c13 → c15 → c14 → c11 → c8 → c4 → c0 → c1 → c5 → c6 → c2 → c3 → c7 → c10 → c9 → c12</p><p>解除 wall:0 后:c16 → c13 → c15 → c14 → c11 → c12 → c9 → c8 → c4 → c0 → c1 → c5 → c6 → c10 → c7 → c3 → c2</p><p>解除 wall:1 后:c16 → c13 → c15 → c12 → c9 → c5 → c6 → c10 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c11 → c14</p></details></article><article><h2>47 · 组合应用与收束 · 六边出口互锁</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 187.9460064798416 450" role="img" aria-label="六边出口互锁"><polygon points="79.17840259193665,45.625 64.38380194395248,71.25 34.79460064798417,71.25 20,45.625 34.79460064798415,20.000000000000004 64.38380194395248,20" fill="#64acf3" stroke="#aaa1c7" stroke-width="2"/><polygon points="123.56220453588912,71.25 108.76760388790495,96.875 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通过前按已走格数切换,通过后保持开启;正确解从第9步末端通过</li></ul><p>关键分叉:第 4 步应走 c4,诱惑路线走 c12。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c5 后:c10 → c9 → c8 → c12 → c13 → c14 → c15 → c11 → c7 → c6 → c5 → c4 → c0 → c1 → c2 → c3</p><p>解除 direction:c9 后:c10 → c9 → c13 → c12 → c8 → c4 → c0 → c1 → c5 → c6 → c2 → c3 → c7 → c11 → c15 → c14</p><p>解除 door:0 后:c10 → c9 → c8 → c12 → c13 → c14 → c15 → c11 → c7 → c3 → c2 → c6 → c5 → c1 → c0 → c4</p></details></article><article><h2>49 · 组合应用与收束 · 先定奇偶,再定节拍</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 368 450" role="img" aria-label="先定奇偶,再定节拍"><polygon points="20,20 102,20 102,102 20,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="102,20 184,20 184,102 102,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="184,20 266,20 266,102 184,102" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="266,20 348,20 348,102 266,102" fill="#f1eef9" stroke="#aaa1c7" 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为第3步,要求奇</li><li>c10 为第10步,要求偶</li><li>门 c3—c7 通过前按已走格数切换,通过后保持开启;正确解从第7步末端通过</li></ul><p>关键分叉:第 2 步应走 c5,诱惑路线走 c10。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c4 后:c9 → c10 → c6 → c5 → c1 → c2 → c3 → c7 → c11 → c14 → c13 → c16 → c15 → c12 → c8 → c4 → c0</p><p>解除 parity:c10 后:c9 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c11 → c14 → c16 → c15 → c12 → c13 → c10 → c6 → c5</p><p>解除 door:0 后:c9 → c8 → c12 → c15 → c16 → c14 → c11 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c6 → c10 → c13</p></details></article><article><h2>50 · 组合应用与收束 · 墙通道门三者联动</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 380 312" role="img" aria-label="墙通道门三者联动"><polygon points="20,20 88,20 88,88 20,88" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,88 88,88 88,156 20,156" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,156 88,156 88,224 20,224" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="20,224 88,224 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font-weight="700">16</text><text x="326" y="64" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c16</text><text x="326" y="114" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="19.72" font-weight="700">17</text><text x="326" y="132" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c17</text></svg></figure><p>c11 → c15 → c14 → c10 → c9 → c5 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c12 → c16 → c17 → c13</p></details></div><h3>推理依据</h3><ul><li>c0 必须右与下拐角</li><li>c6 必须上下直行</li><li>c12 必须左右直行</li><li>墙 c1—c5 封闭该邻接</li><li>墙 c10—c11 封闭该邻接</li><li>门 c6—c7 通过前按已走格数切换,通过后保持开启;正确解从第7步末端通过</li></ul><p>关键分叉:第 6 步应走 c5,诱惑路线走 c13。排除依据:进出方向不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 direction:c0 后:c11 → c15 → c14 → c10 → c9 → c13 → c17 → c16 → c12 → c8 → c4 → c5 → c6 → c7 → c3 → c2 → c1 → c0</p><p>解除 direction:c6 后:c11 → c15 → c14 → c10 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c5 → c9 → c8 → c12 → c16 → c17 → c13</p><p>解除 direction:c12 后:c11 → c15 → c14 → c10 → c9 → c5 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c12 → c13 → c17 → c16</p><p>解除 wall:0 后:c11 → c15 → c14 → c10 → c9 → c13 → c17 → c16 → c12 → c8 → c4 → c0 → c1 → c5 → c6 → c7 → c3 → c2</p><p>解除 wall:1 后:c11 → c10 → c9 → c5 → c6 → c7 → c3 → c2 → c1 → c0 → c4 → c8 → c12 → c16 → c17 → c13 → c14 → c15</p><p>解除 door:0 后:c11 → c15 → c14 → c10 → c9 → c13 → c17 → c16 → c12 → c8 → c4 → c0 → c1 → c2 → c3 → c7 → c6 → c5</p></details></article><article><h2>51 · 组合应用与收束 · 六边综合峰值</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 209.0811502626761 450" role="img" aria-label="六边综合峰值"><polygon points="87.63246010507044,49.28571428571428 70.72434507880283,78.57142857142856 36.908115026267616,78.57142857142856 20,49.285714285714285 36.908115026267595,20.000000000000004 70.72434507880283,20" fill="#f1eef9" stroke="#aaa1c7" stroke-width="2"/><polygon points="138.35680518387326,78.57142857142856 121.44869015760565,107.85714285714285 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c1</p></details></div><h3>推理依据</h3><ul><li>c10 为第4步,要求偶</li><li>c18 为第8步,要求偶</li><li>墙 c10—c11 封闭该邻接</li><li>墙 c10—c13 封闭该邻接</li><li>门 c3—c0 通过前按已走格数切换,通过后保持开启;正确解从第17步末端通过</li></ul><p>关键分叉:第 3 步应走 c9,诱惑路线走 c10。排除依据:该格步号奇偶不符。</p><details><summary>逐项机制必要性反例</summary><p>解除 parity:c10 后:c6 → c7 → c10 → c9 → c12 → c13 → c15 → c18 → c16 → c17 → c14 → c11 → c8 → c5 → c2 → c4 → c3 → c0 → c1</p><p>解除 parity:c18 后:c6 → c7 → c9 → c10 → c12 → c15 → c18 → c16 → c17 → c14 → c13 → c11 → c8 → c5 → c2 → c4 → c3 → c0 → c1</p><p>解除 wall:0 后:c6 → c7 → c9 → c12 → c15 → c18 → c16 → c17 → c14 → c13 → c11 → c10 → c8 → c5 → c2 → c4 → c3 → c0 → c1</p><p>解除 wall:1 后:c6 → c7 → c9 → c12 → c15 → c18 → c16 → c17 → c14 → c11 → c13 → c10 → c8 → c5 → c2 → c4 → c3 → c0 → c1</p><p>解除 door:0 后:c6 → c7 → c9 → c10 → c12 → c13 → c15 → c18 → c16 → c17 → c14 → c11 → c8 → c5 → c2 → c4 → c1 → c0 → c3</p></details></article><article><h2>52 · 组合应用与收束 · 回到双色小题</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" 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font-size="10" fill="#665c78">c1</text><text x="317.5" y="54.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="317.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2</text><text x="62.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">○</text><text x="62.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3</text><text x="232.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="232.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4 · ○</text><text x="317.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">△</text><text x="317.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5</text><text 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font-weight="700">3</text><text x="317.5" y="72.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c2 · ○</text><text x="62.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">11</text><text x="62.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c3 · ○</text><text x="232.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">1</text><text x="232.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c4 · ○</text><text x="317.5" y="139.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">4</text><text x="317.5" y="157.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c5 · △</text><text x="62.5" y="224.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">10</text><text 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text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10 · ○</text><text x="147.5" y="309.5" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="21" font-weight="700">8</text><text x="147.5" y="327.5" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11 · △</text></svg></figure><p>c4 → c1 → c2 → c5 → c9 → c8 → c7 → c11 → c10 → c6 → c3 → c0</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c4—c8 封闭该邻接</li></ul><p>关键分叉:第 2 步应走 c1,诱惑路线走 c5。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c4 → c5 → c2 → c1 → c0 → c3 → c6 → c10 → c11 → c7 → c8 → c9</p><p>解除 wall:0 后:c4 → c8 → c9 → c5 → c2 → c1 → c7 → c11 → c10 → c6 → c3 → c0</p></details></article><article><h2>53 · 组合应用与收束 · 继续还有新花园</h2><div class="boards"><figure><svg xmlns="http://www.w3.org/2000/svg" viewBox="0 0 237.26134197312211 450" role="img" aria-label="继续还有新花园"><polygon points="98.90453678924885,54.166666666666664 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fill="#665c78">c5 · ○</text><text x="59.452268394624426" y="182.83333333333331" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11.441157834441082" font-weight="700">1</text><text x="59.452268394624426" y="200.83333333333331" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c6 · ○</text><text x="118.63067098656106" y="216.99999999999997" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11.441157834441082" font-weight="700">10</text><text x="118.63067098656106" y="234.99999999999997" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c7 · △</text><text x="177.8090735784977" y="251.16666666666663" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11.441157834441082" font-weight="700">8</text><text x="177.8090735784977" y="269.16666666666663" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c8 · △</text><text x="59.452268394624426" y="251.16666666666663" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11.441157834441082" font-weight="700">2</text><text x="59.452268394624426" y="269.16666666666663" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c9 · △</text><text x="118.63067098656106" y="285.3333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11.441157834441082" font-weight="700">9</text><text x="118.63067098656106" y="303.3333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c10 · ○</text><text x="177.8090735784977" y="319.49999999999994" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11.441157834441082" font-weight="700">7</text><text x="177.8090735784977" y="337.49999999999994" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c11 · ○</text><text x="59.452268394624426" y="319.49999999999994" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11.441157834441082" font-weight="700">3</text><text x="59.452268394624426" y="337.49999999999994" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c12 · ○</text><text x="118.63067098656106" y="353.66666666666663" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11.441157834441082" font-weight="700">5</text><text x="118.63067098656106" y="371.66666666666663" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c13 · ○</text><text x="177.8090735784977" y="387.8333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11.441157834441082" font-weight="700">6</text><text x="177.8090735784977" y="405.8333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c14 · △</text><text x="59.452268394624426" y="387.8333333333333" text-anchor="middle" font-family="system-ui,Microsoft YaHei" font-size="11.441157834441082" font-weight="700">4</text><text x="59.452268394624426" y="405.8333333333333" text-anchor="middle" font-family="system-ui" font-size="10" fill="#665c78">c15 · △</text></svg></figure><p>c6 → c9 → c12 → c15 → c13 → c14 → c11 → c8 → c10 → c7 → c5 → c2 → c1 → c4 → c3 → c0</p></details></div><h3>推理依据</h3><ul><li>每步蓝橙交替</li><li>墙 c6—c7 封闭该邻接</li><li>墙 c0—c1 封闭该邻接</li></ul><p>关键分叉:第 8 步应走 c8,诱惑路线走 c10。排除依据:蓝橙颜色必须交替。</p><details><summary>逐项机制必要性反例</summary><p>解除 alternation 后:c6 → c9 → c12 → c15 → c13 → c14 → c11 → c10 → c8 → c7 → c5 → c2 → c4 → c1 → c3 → c0</p><p>解除 wall:0 后:c6 → c7 → c10 → c9 → c12 → c15 → c13 → c14 → c11 → c8 → c5 → c2 → c1 → c4 → c3 → c0</p><p>解除 wall:1 后:c6 → c9 → c12 → c15 → c13 → c14 → c11 → c8 → c10 → c7 → c5 → c2 → c1 → c0 → c3 → c4</p></details></article></html>